使用列表生成 url

Question

我目前正在开发一个程序来帮助管理我的漫画书 collection。我想在相应列表中获取每部漫画的标题、发行编号和等级，并使用这些值填充 url 的 f 字符串部分以获取上次销售数据。到目前为止，我只能让它为每个列表的最后三个条目提供 url。理想情况下，它将提供三个独立的 urls.

示例：

titles = ['thor', 'deadpool', 'spider-man']

issues = ['6', '19', '50']

grades = ['9.8', '9.8', '9.0']

phrases = []

for ti, iss, gr in zip(titles, issues, grades):
    phrases.append(ti)
    phrases.append(iss)
    phrases.append(gr)

for terms in phrases:
    soldurl=f"https://www.ebay.com/sch/900/i.html _from=R40&_nkw={ti}+%23{iss}+{gr}&_sacat=900&Certification=CGC&_dcat=900&rt=nc&LH_Sold=1&LH_Complete=1"

输出：

https://www.ebay.com/sch/900/i.html?_from=R40&_nkw=spider-man+%2350+9.0&_sacat=900&Certification=CGC&_dcat=900&rt=nc&LH_Sold=1&LH_Complete=1

Answer 1

检查这个：

titles = ['thor', 'deadpool', 'spider-man']

issues = ['6', '19', '50']

grades = ['9.8', '9.8', '9.0']

for ti, iss, gr in zip(titles, issues, grades):

    soldurl=f"https://www.ebay.com/sch/900/i.html _from=R40&_nkw={ti}+%23{iss}+{gr}&_sacat=900&Certification=CGC&_dcat=900&rt=nc&LH_Sold=1&LH_Complete=1"
    print(soldurl)

输出：

https://www.ebay.com/sch/900/i.html _from=R40&_nkw=thor+%236+9.8&_sacat=900&Certification=CGC&_dcat=900&rt=nc&LH_Sold=1&LH_Complete=1
https://www.ebay.com/sch/900/i.html _from=R40&_nkw=deadpool+%2319+9.8&_sacat=900&Certification=CGC&_dcat=900&rt=nc&LH_Sold=1&LH_Complete=1
https://www.ebay.com/sch/900/i.html _from=R40&_nkw=spider-man+%2350+9.0&_sacat=900&Certification=CGC&_dcat=900&rt=nc&LH_Sold=1&LH_Complete=1

Answer 2

这样的东西可能有用吗？

soldurls=["https://www.ebay.com/sch/900/i.html _from=R40&_nkw={ti}+%23{iss}+{gr}&_sacat=900&Certification=CGC&_dcat=900&rt=nc&LH_Sold=1&LH_Complete=1" for ti, iss, gr in zip(titles, issues, grades)]

应该 return 一个 url 列表。

使用列表生成 url

Using lists to generate url

python

list

f-string