带参数的函数 React-Native

Question

我有这个功能

export default async function get_happy_songs(param) {

    let emotion = param;
    // console.log(emotion)
    ...

    }

有时我想这样做 :

let arg = value;
let happy_songs =  await get_happy_songs(arg);

但我知道函数定义语法有问题，所以我应该如何处理我的函数才能获得该参数？

Answer 1

尝试一下，希望对你有用

export async function get_happy_songs(param) {
let emotion = param;
console.log(emotion)
return true
}




 async componentDidMount() {
 
    let happy_songs =  await get_happy_songs('Love you like  you do');
    console.log(happy_songs)
}