Oracle SQL 显示一个变量除以另一个变量的结果

Question

我需要计算 GROSS_AMOUNT

的年初至今每周平均值

在下面的脚本中，代码的第一部分获取周数。代码的第二部分获取同一时间段的 YTD 总和

如何编写 SQL 以便检索 YtdTotal/TotalWeeks 的实际值？

SELECT YtdTotal/TotalWeeks 来自双重；不起作用

-- STORES NUMBER OF WEEKS SINCE BEGINING OF YEAR INTO THE VARIABLE, TotalWeeks
DECLARE
    TotalWeeks NUMBER;
BEGIN
    SELECT to_number(to_char(sysdate, 'WW')) - to_number(to_char(trunc(sysdate, 'year'),'WW'))
    INTO TotalWeeks
    FROM DUAL
    -- (retrieves number of weeks since beginning of year)
END

-- STORES THE SUM OF GROSS)AMOUNT FOR THE WEEKS CALCULATED ABOVE - INTO THE 
DECLARE
    VARIABLE, YtdTotal
BEGIN
    SELECT SUM(GROSS_AMOUNT) 
    INTO YtdTotal
    FROM PARENTS
    WHERE process_date BETWEEN
    (next_day(TRUNC(sysdate, 'year'),'SUN'))
    AND
    (next_day(TRUNC(sysdate),'SAT')-7);
END;

Answer 1

不要使用两个单独的匿名 PL/SQL 块 - 将它们合并为一个！

如果你想要 return 结果，那么 - 而不是匿名 PL/SQL 块 - 创建一个函数 .

CREATE OR REPLACE FUNCTION f_test
  return NUMBER
IS
   totalweeks  NUMBER;
   ytdtotal    NUMBER;
   result      NUMBER;
BEGIN
   -- STORES NUMBER OF WEEKS SINCE BEGINING OF YEAR INTO THE VARIABLE, TotalWeeks
   SELECT   TO_NUMBER (TO_CHAR (SYSDATE, 'WW'))
          - TO_NUMBER (TO_CHAR (TRUNC (SYSDATE, 'year'), 'WW'))
     INTO totalweeks
     FROM DUAL;

   -- (retrieves number of weeks since beginning of year)

   -- STORES THE SUM OF GROSS)AMOUNT FOR THE WEEKS CALCULATED ABOVE - INTO THE
   SELECT SUM (gross_amount)
     INTO ytdtotal
     FROM parents
    WHERE process_date BETWEEN (NEXT_DAY (TRUNC (SYSDATE, 'year'), 'SUN'))
                           AND (NEXT_DAY (TRUNC (SYSDATE), 'SAT') - 7);

   -- the final result
   result := ytdtogal / totalweeks;
   RETURN result;
END;
/

用作

select f_test from dual;

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