如何过滤 powershell stdout

Question

Ansible：2.9 电力外壳：5 OS: w2k16 服务器

大家好！

我搜索了ansible推出的PowerShell过滤Format-Hex标准输出的方法

代码：

win_shell: |
 Format-Hex C:\test.txt
register: recorder


debug:
  msg: {{ recorder }}

我明白了：

            0  1  2  3  4  5  6  7  8  9  A  B  C  D  E  F

00000000   42 4D 5E 00 00 00 00 00 00 00 36 00 00 00 28 00  BM^.......6...(. 
00000010   00 00 0A 00 00 00 01 00 00 00 01 00 20 00 00 00  ............ ... 
00000020   00 00 00 00 00 00 C4 0E 00 00 C4 0E 00 00 00 00  ......Ä...Ä..... 
00000030   00 00 00 00 00 00 B7 59 71 FF B7 59 71 FF B7 59  ......•Yq.•Yq.•Y 
00000040   71 FF B7 59 71 FF B7 59 71 FF B7 59 71 FF B7 59  q.•Yq.•Yq.•Yq.•Y 
00000050   71 FF B7 59 71 FF B7 59 71 FF B7 59 71 FF        q.•Yq.•Yq.•Yq.

但我只想要：

所有行都包含 Hexa 数据：

42 4D 5E 00 00 00 00 00 00 00 36 00 00 00 28 00
...
...

再次感谢！

Answer 1

试试这个，对我有用：

PS /~> cat .\test.txt
            0  1  2  3  4  5  6  7  8  9  A  B  C  D  E  F

00000000   42 4D 5E 00 00 00 00 00 00 00 36 00 00 00 28 00  BM^.......6...(. 
00000010   00 00 0A 00 00 00 01 00 00 00 01 00 20 00 00 00  ............ ... 
00000020   00 00 00 00 00 00 C4 0E 00 00 C4 0E 00 00 00 00  ......Ä...Ä..... 
00000030   00 00 00 00 00 00 B7 59 71 FF B7 59 71 FF B7 59  ......•Yq.•Yq.•Y 
00000040   71 FF B7 59 71 FF B7 59 71 FF B7 59 71 FF B7 59  q.•Yq.•Yq.•Yq.•Y 
00000050   71 FF B7 59 71 FF B7 59 71 FF B7 59 71 FF        q.•Yq.•Yq.•Yq.

PS /~> cat .\test.txt|select -Skip 1|%{($_ -split '\s{2,}')[1]}
42 4D 5E 00 00 00 00 00 00 00 36 00 00 00 28 00
00 00 0A 00 00 00 01 00 00 00 01 00 20 00 00 00
00 00 00 00 00 00 C4 0E 00 00 C4 0E 00 00 00 00
00 00 00 00 00 00 B7 59 71 FF B7 59 71 FF B7 59
71 FF B7 59 71 FF B7 59 71 FF B7 59 71 FF B7 59
71 FF B7 59 71 FF B7 59 71 FF B7 59 71 FF

PS /~>

跳过第一行 (Header)

对于每一行，在有 2 个或更多空格的地方拆分，生成 3 项数组，我们得到位置 1 上的项，这是您感兴趣的输出。