SQL 服务器：查询输出

Question

请帮助我处理以下查询输出。

这是期望的输出：

请注意 xml 节点 <Comp1_1> 是 Comp+GroupID+SummaryID.

的组合

示例代码 table 和数据：

DROP TABLE IF EXISTS #Summary

CREATE TABLE #Summary
(
    Summaryid INT, 
    GroupID INT, 
    AnswerID INT, 
    Community VARCHAR(50), 
    ChildRecordID INT, 
    Features VARCHAR(100)
)

INSERT INTO #Summary(Summaryid, GroupID, AnswerID, Community, ChildRecordID, Features)
VALUES (1, 1, 15, 'Class A', 1, 'Good at baseball'),
       (2, 1, 16, 'Class C', 1, 'Passionate Gamer'),
       (2, 1, 16, 'Class C', 2, 'Nature Lover'),
       (3, 2, 17, 'Class D', 1, 'Loves doing Yoga')
       
SELECT * FROM #Summary

在此先感谢您的查阅。

干杯。

Answer 1

select 
SummaryId as 'SummaryID', GroupID as 'Group', AnswerID as 'AnswerID',
cast(concat('<Comp', GroupId, '_', SummaryId,'>', --concat for compxyz element name
(
--community per summary,group,answer
select y.Community,
(
    --childrows per community (per summary, group, answer)
    select z.ChildRecordID, z.Features
    from #Summary as z
    where z.Summaryid = x.Summaryid
    and z.GroupId = x.GroupID
    and z.AnswerID = x.AnswerID
    and z.Community = y.Community
    for xml path('ChildRecords'), type
)
from #Summary as y --this is not needed if there can be only one/single community per summary&group&answer..just add community in the outer groupby of table x and use columns of table x to get the childrows from table z
where y.Summaryid = x.Summaryid
and y.GroupID = x.GroupID
and y.AnswerID = x.AnswerID
group by y.Community
for xml path('') --if there can be many communities per summary&group&answer then this will result in <community a><childrows of a><community b><childrows of b>....
), 
'</Comp', GroupId, '_', SummaryId, '>') as xml)
from #Summary as x
group by Summaryid, GroupID, AnswerID
for xml path('SummaryDetails'), root('Summary');

SQL 服务器：查询输出

SQL Server : query output

xml

sql

sql-server

xquery