预期 python 中的缩进块与烧瓶

Question

我在尝试从训练数据中获取响应时遇到此错误，我不确定原因：

“需要一个缩进块（第 55 行）pylint（语法错误）”

这是代码


app = Flask(__name__);
CORS(app)
@app.route("/bot", methods=["POST"])

#response
def response():
    query = dict(request.form)['query']
   # res = query + " " 
    sentence = tokenize(sentence)
    X = bag_of_words(sentence, all_words)
    X = X.reshape(1, X.shape[0])
    X = torch.from_numpy(X).to(device)

    output = model(X)
    _, predicted = torch.max(output, dim=1)

    tag = tags[predicted.item()]

    probs = torch.softmax(output, dim=1)
    prob = probs[0][predicted.item()]
    if prob.item() > 0.75:
        for intent in intents['intents']:
            if tag == intent["tag"]:
                
    # print(f"{bot_name}: {random.choice(intent['responses'])}")
    return jsonify({"response" :  random.choice(intent['responses'])}) #HERE IS THE ERROR
    
    else:
        return jsonify({"response" : "I do not understand..."})
     
if __name__=="__main__":
    app.run(host="0.0.0.0",)

随机选择的想法是得到一个包含我之前定义的一些特征的响应....

Answer 1

问题似乎出在这一行，能否请您检查一下该块中的缩进是否合适

if prob.item() > 0.75:
        for intent in intents['intents']:
            if tag == intent["tag"]:

Answer 2

因此，您创建了一个 if 条件并且没有在其中编写任何语句。这就是它导致错误的原因。行 return jsonify({"response": random.choice(intent['responses'])}) 应该在 if 条件 if tag == intent["tag"].

内

if prob.item() > 0.75:
    for intent in intents['intents']:
        if tag == intent["tag"]:

# print(f"{bot_name}: {random.choice(intent['responses'])}")
            return jsonify({"response": random.choice(intent['responses'])})  # HERE IS THE ERROR

else:
    return jsonify({"response": "I do not understand..."})

预期 python 中的缩进块与烧瓶

expected an indented block in python with flask

python

syntax-error

flask