如何使用 Type 使 pydantic Field 接受子类?
How to make a pydantic Field accept subclasses using Type?
我试图让一个 Pydantic 模型中的字段接受我单独定义的一组 BaseModel 派生的 类 或 sub类 中的任何一个。阅读 docs here,我天真地做了下面的事情,但失败了;然后我意识到我误解了文档,并且在这种情况下“一个字段可能只接受 类(不是实例)”,而且那个例子中的 Foo 和 Bar 不是从 BaseModel 本身派生的(是有那么重要吗?)。
我猜我只是从一开始就误解了这一点,所以我的问题是:有没有正确的方法来做我想做的事情而不在 sub类 上使用 Union ,或者其他更好的方式?
奖金问题:只能接受 类 而不能接受实例的常见用例是什么?
MRE:
from pydantic import BaseModel
from typing import Type, Union
class Foo(BaseModel):
pass
class Bar(Foo):
pass
class Baz(Foo):
pass
class Container(BaseModel):
some_foo: Type[Foo] # this fails
# this will run successfully --> some_foo: Union[Bar, Baz]
b = Baz()
c = Container(some_foo = b)
# Traceback (most recent call last):
# File "mre.py", line 20, in <module>
# c = Container(some_foo = b)
# File "pydantic/main.py", line 400, in pydantic.main.BaseModel.__init__
# pydantic.error_wrappers.ValidationError: 1 validation error for Container
# some_foo
# subclass of Foo expected (type=type_error.subclass; expected_class=Foo)
这比看起来更棘手。
这是一个使用 pydantic
的 validator 的解决方案,但也许还有更“花哨”的方法。
from pydantic import BaseModel, validator
from typing import Any
class Foo(BaseModel):
pass
class Bar(Foo):
pass
class Baz(Foo):
pass
class NotFoo(BaseModel):
pass
class Container(BaseModel):
some_foo: Any
@validator("some_foo")
def validate_some_foo(cls, val):
if issubclass(type(val), Foo):
return val
raise TypeError("Wrong type for 'some_foo', must be subclass of Foo")
b = Bar()
c = Container(some_foo=b)
# Container(some_foo=Bar())
n = NotFoo()
c = container(some_foo=n)
# Traceback (most recent call last):
# File "/path/to/file.py", line 64, in <module>
# c = Container(some_foo=n)
# File "pydantic/main.py", line 400, in pydantic.main.BaseModel.__init__
# pydantic.error_wrappers.ValidationError: 1 validation error for Container
# some_foo
# Wrong type for 'some_foo', must be subclass of Foo (type=type_error)
请注意,自定义验证器必须引发 ValueError
或 TypeError
(或其子 class),以便 pydantic
能够正确地重新提出 ValudationError
.
您可能希望使用特定的 class(而不是 class 的实例)作为字段类型的一个原因是当您希望稍后使用该字段实例化某些内容时关于使用该字段。
这是一个例子:
from pydantic import BaseModel
from typing import Optional, Type
class Foo(BaseModel):
# x is NOT optional
x: int
class Bar(Foo):
y: Optional[str]
class Baz(Foo):
z: Optional[bool]
class NotFoo(BaseModel):
# a is NOT optional
a: str
class ContainerForClass(BaseModel):
some_foo_class: Type[Foo]
c = ContainerForClass(some_foo_class=Bar)
# At this point you know that you will use this class for something else
# and that x must be always provided and it must be an int:
d = c.some_foo_class(x=5, y="some string")
# Baz(x=5, z=None)
c = ContainerForClass(some_foo_class=Baz)
# Same here with x:
e = c.some_foo_class(x=6, z=True)
# Baz(x=6, z=True)
# Would't work with this:
c = ContainerForClass(some_foo_class=NotFoo)
# Traceback (most recent call last):
# File "/path/to/file.py", line 98, in <module>
# c = ContainerForClass(some_foo_class=NotFoo)
# File "pydantic/main.py", line 400, in pydantic.main.BaseModel.__init__
# pydantic.error_wrappers.ValidationError: 1 validation error for ContainerForClass
# some_foo_class
# subclass of Foo expected (type=type_error.subclass; expected_class=Foo
我试图让一个 Pydantic 模型中的字段接受我单独定义的一组 BaseModel 派生的 类 或 sub类 中的任何一个。阅读 docs here,我天真地做了下面的事情,但失败了;然后我意识到我误解了文档,并且在这种情况下“一个字段可能只接受 类(不是实例)”,而且那个例子中的 Foo 和 Bar 不是从 BaseModel 本身派生的(是有那么重要吗?)。
我猜我只是从一开始就误解了这一点,所以我的问题是:有没有正确的方法来做我想做的事情而不在 sub类 上使用 Union ,或者其他更好的方式?
奖金问题:只能接受 类 而不能接受实例的常见用例是什么?
MRE:
from pydantic import BaseModel
from typing import Type, Union
class Foo(BaseModel):
pass
class Bar(Foo):
pass
class Baz(Foo):
pass
class Container(BaseModel):
some_foo: Type[Foo] # this fails
# this will run successfully --> some_foo: Union[Bar, Baz]
b = Baz()
c = Container(some_foo = b)
# Traceback (most recent call last):
# File "mre.py", line 20, in <module>
# c = Container(some_foo = b)
# File "pydantic/main.py", line 400, in pydantic.main.BaseModel.__init__
# pydantic.error_wrappers.ValidationError: 1 validation error for Container
# some_foo
# subclass of Foo expected (type=type_error.subclass; expected_class=Foo)
这比看起来更棘手。
这是一个使用 pydantic
的 validator 的解决方案,但也许还有更“花哨”的方法。
from pydantic import BaseModel, validator
from typing import Any
class Foo(BaseModel):
pass
class Bar(Foo):
pass
class Baz(Foo):
pass
class NotFoo(BaseModel):
pass
class Container(BaseModel):
some_foo: Any
@validator("some_foo")
def validate_some_foo(cls, val):
if issubclass(type(val), Foo):
return val
raise TypeError("Wrong type for 'some_foo', must be subclass of Foo")
b = Bar()
c = Container(some_foo=b)
# Container(some_foo=Bar())
n = NotFoo()
c = container(some_foo=n)
# Traceback (most recent call last):
# File "/path/to/file.py", line 64, in <module>
# c = Container(some_foo=n)
# File "pydantic/main.py", line 400, in pydantic.main.BaseModel.__init__
# pydantic.error_wrappers.ValidationError: 1 validation error for Container
# some_foo
# Wrong type for 'some_foo', must be subclass of Foo (type=type_error)
请注意,自定义验证器必须引发 ValueError
或 TypeError
(或其子 class),以便 pydantic
能够正确地重新提出 ValudationError
.
您可能希望使用特定的 class(而不是 class 的实例)作为字段类型的一个原因是当您希望稍后使用该字段实例化某些内容时关于使用该字段。
这是一个例子:
from pydantic import BaseModel
from typing import Optional, Type
class Foo(BaseModel):
# x is NOT optional
x: int
class Bar(Foo):
y: Optional[str]
class Baz(Foo):
z: Optional[bool]
class NotFoo(BaseModel):
# a is NOT optional
a: str
class ContainerForClass(BaseModel):
some_foo_class: Type[Foo]
c = ContainerForClass(some_foo_class=Bar)
# At this point you know that you will use this class for something else
# and that x must be always provided and it must be an int:
d = c.some_foo_class(x=5, y="some string")
# Baz(x=5, z=None)
c = ContainerForClass(some_foo_class=Baz)
# Same here with x:
e = c.some_foo_class(x=6, z=True)
# Baz(x=6, z=True)
# Would't work with this:
c = ContainerForClass(some_foo_class=NotFoo)
# Traceback (most recent call last):
# File "/path/to/file.py", line 98, in <module>
# c = ContainerForClass(some_foo_class=NotFoo)
# File "pydantic/main.py", line 400, in pydantic.main.BaseModel.__init__
# pydantic.error_wrappers.ValidationError: 1 validation error for ContainerForClass
# some_foo_class
# subclass of Foo expected (type=type_error.subclass; expected_class=Foo