在用 Key 中的当前值递增另一个变量的值后，我得到一个 KeyError，不知道我遗漏了什么

Question

from random import shuffle
def makeDeck():
    Deck = []
    for i in range(4):
        valueCards = ["A", "K", "J", "Q"]
        Deck.append(valueCards)
        for cards in range(2,11):
            Deck.append(cards)
    shuffle(Deck)
    print(Deck)
    return Deck

我对 class 做了一些更改，方法是使 self.score = self.setScore() 和以前一样，当我将它设置为一个数字时，该值根本没有更新。

class Player:
    def __init__(self, drawn = []):
        self.drawn = drawn
        
        self.score = self.setScore()
    def __str__(self):
        currentDraw = ""
        for cards in self.drawn:
            currentDraw += str(cards) + " "
        finalDraw = currentDraw + "score: " + str(self.score)
        return finalDraw


    def setScore(self):
        self.score = 0

        cardValues = {"A":11, "K":10, "J":10, "Q":10,
                      "2":2, "3":3, "4":4, "5":5, "6":6,
                      "7":7, "8":8, "9":9, "10":10}
        for cards in self.drawn:
            self.score += cardValues[cards]
        return self.score

我通过打印出一些像这样的值来测试我正在更新，这些值在控制台上打印得很好。

Player1 = Player(["4", "9"])
print(Player1)

当我添加下一位时，我收到错误消息，但不确定原因。

cardDeck = makeDeck()
firstDraw = [cardDeck.pop()]
DrawOne = " ".join(str(e) for e in firstDraw)
secondDraw = [cardDeck.pop()]
DrawTwo = " ".join(str(j) for j in secondDraw)
thirdDraw = [cardDeck.pop()]
First = Player(firstDraw)
player1 = Player(secondDraw)
player2 = Player(thirdDraw)
defeat = False

while(defeat != True):
    choice = input("Higher or lower?: ")
    if choice == "Higher" or "higher":
        if DrawOne < DrawTwo:
            counter  += 1
            print(player1.score)
    if choice == "Lower" or "lower":
        if DrawOne > DrawTwo:
            counter += 1
            print(player1.score)
            player1
    else:
        defeat = True
        print(player1.score)
        print("Defeat")

Answer 1

在 Makedeck 中你有这些行：

valueCards = ["A", "K", "J", "Q"]
Deck.append(valueCards)

这导致 Deck 成为一个元素的列表，该元素是 4 个字符串的列表。

您可以检查 makedeck() = [["A", "K", "J", "Q"], 2, 3, 4, 5, 6, 7, 8, 的结果。 ..]，因此 deck.pop() = [“A”、“K”、“J”、“Q”]。你真正想要的是这个：

Deck.extend(valueCards)

这将产生一个包含 4 个字符串的列表，并且在函数的末尾 returns ["A", "K", "J", "Q", 2, 3, .. .]，这就是你想要的。

在第一种情况下，您检查元素 ["A", "K", "J", "Q"] 是否作为字典的键存在，但事实并非如此。

Answer 2

我修复了 KeyError 和其他一些错误，包括：

KeyError问题，你的卡片类型是整数，而dict cardValues key是字符串
DriesDS 回答了 makeDeck 错误
变量 counter 未定义且从未真正使用过
if-else语法错误和逻辑错误

代码：

from random import shuffle
def makeDeck():
    Deck = []
    for i in range(4):
        valueCards = ["A", "K", "J", "Q"]
        Deck.extend(valueCards)#answerd by DriesDS
        for cards in range(2,11):
            Deck.append(cards)
    shuffle(Deck)
    print(Deck)
    return Deck

class Player:
    def __init__(self, drawn = []):
        self.drawn = drawn
        
        self.score = self.setScore()
    def __str__(self):
        currentDraw = ""
        for cards in self.drawn:
            currentDraw += str(cards) + " "
        finalDraw = currentDraw + "score: " + str(self.score)
        return finalDraw


    def setScore(self):
        self.score = 0

        cardValues = {"A":11, "K":10, "J":10, "Q":10,
                      "2":2, "3":3, "4":4, "5":5, "6":6,
                      "7":7, "8":8, "9":9, "10":10}
        for cards in self.drawn:
            self.score += cardValues[str(cards)]#your cards type is interger,while dict cardValues key are strings
        return self.score

Player1 = Player(["4", "9"])
print(Player1)
cardDeck = makeDeck()
firstDraw = [cardDeck.pop()]
DrawOne = " ".join(str(e) for e in firstDraw)
secondDraw = [cardDeck.pop()]
DrawTwo = " ".join(str(j) for j in secondDraw)
thirdDraw = [cardDeck.pop()]
First = Player(firstDraw)
player1 = Player(secondDraw)
player2 = Player(thirdDraw)
defeat = False
counter = 0

while(defeat != True):
    choice = input("Higher or lower?: ")
    if choice == "Higher" or choice == "higher":
        if DrawOne < DrawTwo:
            counter  += 1
            print(player1.score)
    elif choice == "Lower" or choice == "lower":
        if DrawOne > DrawTwo:
            counter += 1
            print(player1.score)
    else:
        defeat = True
        print(player1.score)
        print("Defeat")

结果：

4 9 score: 13
['A', 6, 6, 9, 5, 7, 'A', 4, 'Q', 5, 7, 5, 9, 8, 9, 4, 'K', 7, 'J', 3, 8, 'K', 2, 9, 'J', 4, 2, 8, 'K', 10, 7, 'A', 3, 'Q', 6, 2, 5, 6, 'Q', 3, 'J', 10, 2, 10, 4, 10, 'Q', 'A', 3, 8, 'K', 'J']
Higher or lower?: higher
10
Higher or lower?: lower
Higher or lower?: 1
10
Defeat

在用 Key 中的当前值递增另一个变量的值后，我得到一个 KeyError，不知道我遗漏了什么

I'm getting a KeyError after incrementing the value of another variable with the current value in the Key, don't know what I'm missing

python

dictionary

keyerror