将具有相同 ItemNumber 的节点加入一行

Question

一些供应商定期发布包含商品价格的 XML 文件。文件中有两种价格：目录价（list Price）和折扣价（discount Price）

<prices>
<price>
    <itemNumber>100</itemNumber>
    <currency>PLN</currency>
    <amount>2.98</amount>
    <type>listPrice</type>
</price>
<price>
    <itemNumber>100</itemNumber>
    <currency>PLN</currency>
    <amount>1.19</amount>
    <type>discountPrice</type>
</price>
<price>
    <itemNumber>101</itemNumber>
    <currency>PLN</currency>
    <amount>3.88</amount>
    <type>listPrice</type>
</price>
<price>
    <itemNumber>101</itemNumber>
    <currency>PLN</currency>
    <amount>2.76</amount>
    <type>discountPrice</type>
</price>
<price>
    <itemNumber>102</itemNumber>
    <currency>PLN</currency>
    <amount>4.55</amount>
    <type>listPrice</type>
</price>
<price>
    <itemNumber>102</itemNumber>
    <currency>PLN</currency>
    <amount>3.20</amount>
    <type>discountPrice</type>
</price>
<price>
    <itemNumber>103</itemNumber>
    <currency>PLN</currency>
    <amount>3.38</amount>
    <type>listPrice</type>
</price>
<price>
    <itemNumber>103</itemNumber>
    <currency>PLN</currency>
    <amount>2.90</amount>
    <type>discountPrice</type>
</price>
<price>
    <itemNumber>104</itemNumber>
    <currency>PLN</currency>
    <amount>2.98</amount>
    <type>listPrice</type>
</price>
<price>
    <itemNumber>104</itemNumber>
    <currency>PLN</currency>
    <amount>1.19</amount>
    <type>discountPrice</type>
</price>
</prices>

目前我正在将 XML 文件上传到数据库，然后我正在使用从 xml table.[=13 中获取的数据创建 tmp table =]

SELECT
@SupplierID     AS SupplierID
, a.product.query('itemNumber').value('.', 'varchar(50)')   AS SupplierCode
, a.product.query('amount').value('.', 'MONEY') AS PricePLN
, a.product.query('type').value('.', 'varchar(50)') AS NetPriceTypePLN
, GETDATE()         AS CreateDate
INTO Prices_tmp
FROM ImportedXML x(nolock)
OUTER APPLY x.xmlData.nodes('prices/price') as a(product)
where 
x.Fileid = 111

我正在努力解决的问题是如何阅读 XML 以在一行中获得两个价格喜欢：

ItemNumber | ListedPriceAmount | discountPriceAmount
100        | 2.98              | 1.19
101        | 3.88              | 2.76
102        | 4.55              | 3.20
103        | 3.38              | 2.90

你能帮帮我吗？我花了很多时间自己尝试。

Answer 1

请尝试以下解决方案。

要提及的要点：

适当的 XML 粉碎成 relational/rectangular 格式。
简单模拟PIVOT操作，达到预期效果输出。

SQL

DECLARE @xml XML = 
N'<prices>
    <price>
        <itemNumber>100</itemNumber>
        <currency>PLN</currency>
        <amount>2.98</amount>
        <type>listPrice</type>
    </price>
    <price>
        <itemNumber>100</itemNumber>
        <currency>PLN</currency>
        <amount>1.19</amount>
        <type>discountPrice</type>
    </price>
    <price>
        <itemNumber>101</itemNumber>
        <currency>PLN</currency>
        <amount>3.88</amount>
        <type>listPrice</type>
    </price>
    <price>
        <itemNumber>101</itemNumber>
        <currency>PLN</currency>
        <amount>2.76</amount>
        <type>discountPrice</type>
    </price>
    <price>
        <itemNumber>102</itemNumber>
        <currency>PLN</currency>
        <amount>4.55</amount>
        <type>listPrice</type>
    </price>
    <price>
        <itemNumber>102</itemNumber>
        <currency>PLN</currency>
        <amount>3.20</amount>
        <type>discountPrice</type>
    </price>
    <price>
        <itemNumber>103</itemNumber>
        <currency>PLN</currency>
        <amount>3.38</amount>
        <type>listPrice</type>
    </price>
    <price>
        <itemNumber>103</itemNumber>
        <currency>PLN</currency>
        <amount>2.90</amount>
        <type>discountPrice</type>
    </price>
    <price>
        <itemNumber>104</itemNumber>
        <currency>PLN</currency>
        <amount>2.98</amount>
        <type>listPrice</type>
    </price>
    <price>
        <itemNumber>104</itemNumber>
        <currency>PLN</currency>
        <amount>1.19</amount>
        <type>discountPrice</type>
    </price>
</prices>';

WITH rs AS
(
    SELECT c.value('(itemNumber/text())[1]', 'varchar(50)') AS ItemNumber 
        , c.value('(amount/text())[1]', 'money') AS amount 
        , c.value('(type/text())[1]', 'varchar(50)') AS type 
    FROM @xml.nodes('/prices/price') AS t(c)
)
-- simulates PIVOT operation
SELECT DISTINCT
    ItemNumber
    , MAX(IIF(type = 'listPrice', amount, 0)) OVER (PARTITION BY ItemNumber) AS ListedPriceAmount
    , MAX(IIF(type = 'discountPrice', amount, 0)) OVER (PARTITION BY ItemNumber) AS discountPriceAmount
FROM rs;

输出

+------------+-------------------+---------------------+
| ItemNumber | ListedPriceAmount | discountPriceAmount |
+------------+-------------------+---------------------+
|        100 |              2.98 |                1.19 |
|        101 |              3.88 |                2.76 |
|        102 |              4.55 |                3.20 |
|        103 |              3.38 |                2.90 |
|        104 |              2.98 |                1.19 |
+------------+-------------------+---------------------+

Answer 2

如果主元运算太难记不住，试试这个：

DECLARE @xml XML = '...'

WITH rs AS
(
    SELECT c.value('(itemNumber/text())[1]', 'varchar(50)') AS ItemNumber 
                , c.value('(amount/text())[1]', 'money') AS amount 
                , c.value('(type/text())[1]', 'varchar(50)') AS type 
    FROM @xml.nodes('/prices/price') AS t(c)
), sr as
(
    SELECT
            ItemNumber,
            amount ListedPriceAmount,
            0 discountPriceAmount 
    FROM rs
    where type = 'listPrice'
    union
    SELECT
            ItemNumber,
            0 ListedPriceAmount,
            amount discountPriceAmount 
    FROM rs
    where type = 'discountPrice'
)
select ItemNumber, sum(ListedPriceAmount) ListedPriceAmount, sum(discountPriceAmount) discountPriceAmount
from sr
group by ItemNumber

结果与 Yitzhak 的回答相同。

将具有相同 ItemNumber 的节点加入一行

Joining nodes with the same ItemNumber into one row

xml

sql

tsql

sql-server

xquery