将值分配给数组然后在 symfony 中将其编码为 json 的最佳方法或实践

Question

所以目前我有这个代码：

//getting products
    $productsFirst = $this->productRepository->findBy(
        ['weather' => $conditionFirst],
        ['price' => 'ASC'],
        2
    );
    

    $productsSecond = $this->productRepository->findBy(
        ['weather' => $conditionSecond],
        ['price' => 'ASC'],
        2
    );

    $productsThird = $this->productRepository->findBy(
        ['weather' => $conditionThird],
        ['price' => 'ASC'],
        2
    );

    //serializing products
    $normalizers = [
        new ObjectNormalizer(),
    ];
    $encoders = [
        new JsonEncoder(),
    ];
    $serializer = new Serializer($normalizers, $encoders);
    $productsFirst = $serializer->serialize($productsFirst, format:'json',);
    $productsSecond = $serializer->serialize($productsSecond, format:'json',);
    $productsThird = $serializer->serialize($productsThird, format:'json',);
    


    $arr = array(
        $city => array(
            "weather_forecast" => $conditionFirst,
            "date" => $dateFirst,
            "product" => $productsFirst
        ),
        array(
            "weather_forecast" => $conditionSecond,
            "date" => $dateSecond,
            "product" => $productsSecond
        ),
        array(
            "weather_forecast" => $conditionThird,
            "date" => $dateThird,
            "product" => $productsThird
        )
    );

    
  
    return $arr = json_encode($arr, | JSON_PRETTY_PRINT);

我收到了这个 json 回复：

   {
    "London": {
        "weather_forecast": "clear",
        "date": "2021-06-08",
        "product": "[{\"id\":903,\"sku\":\"6456909228\",\"name\":\"Abdul Bergstrom\",\"price\":0.45,\"weather\":\"clear\"},{\"id\":1074,\"sku\":\"6540442971\",\"name\":\"Gladys Kirlin\",\"price\":6.73,\"weather\":\"clear\"}]"
    },
    "0": {
        "weather_forecast": "clear",
        "date": "2021-06-09",
        "product": "[{\"id\":903,\"sku\":\"6456909228\",\"name\":\"Abdul Bergstrom\",\"price\":0.45,\"weather\":\"clear\"},{\"id\":1074,\"sku\":\"6540442971\",\"name\":\"Gladys Kirlin\",\"price\":6.73,\"weather\":\"clear\"}]"
    },
    "1": {
        "weather_forecast": "light-rain",
        "date": "2021-06-10",
        "product": "[{\"id\":1103,\"sku\":\"8486705088\",\"name\":\"Dr. Aniyah Stehr IV\",\"price\":1.62,\"weather\":\"light-rain\"},{\"id\":931,\"sku\":\"3629804527\",\"name\":\"Jean Kirlin\",\"price\":5.11,\"weather\":\"light-rain\"}]"
    }
}

但我想从 json 中删除 id 和天气。解码然后再次编码似乎是一种糟糕的方法。我可以在将它们序列化为 json 之前访问所需的值吗？我想要这样的东西：

{
"London": {
    "weather_forecast": "clear",
    "date": "2021-06-09",
    "product": [
            {
                "name": "Dr. Aniyah Stehr IV",
                "sku": "8486705088",
                "price": "94.68"
            },
            {
                "name": "Jean Kirlin",
                "sku": "3629804527",
                "price": "10.76"
            }
},
"0": {
    "weather_forecast": "clear",
    "date": "2021-06-09",
    "product": [
            {
                "name": "Dr. Aniyah Stehr IV",
                "sku": "8486705088",
                "price": "94.68"
            },
            {
                "name": "Jean Kirlin",
                "sku": "3629804527",
                "price": "10.76"
            }

抱歉，如果这是一个愚蠢的问题，我仍然了解 symfony。

Answer 1

您不需要序列化您的实体数组。

您可以在您的实体中声明

use JsonSerializable;

/**
* @Entity(repositoryClass="App\Entity\MyEntity::class")
* @Table(name="user")
*/
class MyEntity implements JsonSerializable
{
    /** @Column(length=50) */
    private $name;

    /** @Column(length=50) */
    private $sku;

    /** @Column(length=50) */
    private $price;

    public function jsonSerialize()
    {
        return array(
            'name' => $this->name,
            'sku'=> $this->sku,
            'price'=> $this->price,
        );
    }
}

然后调用你的代码，你可以直接在这些实体上调用json_encode：

//getting products
$productsFirst = $this->productRepository->findBy(
    ['weather' => $conditionFirst],
    ['price' => 'ASC'],
    2
);


$productsSecond = $this->productRepository->findBy(
    ['weather' => $conditionSecond],
    ['price' => 'ASC'],
    2
);

$productsThird = $this->productRepository->findBy(
    ['weather' => $conditionThird],
    ['price' => 'ASC'],
    2
);

$arr = array(
    $city => array(
        "weather_forecast" => $conditionFirst,
        "date" => $dateFirst,
        "product" => $productsFirst
    ),
    array(
        "weather_forecast" => $conditionSecond,
        "date" => $dateSecond,
        "product" => $productsSecond
    ),
    array(
        "weather_forecast" => $conditionThird,
        "date" => $dateThird,
        "product" => $productsThird
    )
);



return $arr = json_encode($arr, | JSON_PRETTY_PRINT);

将值分配给数组然后在 symfony 中将其编码为 json 的最佳方法或实践

Best way or practice to assign values to array and then encode it to json in symfony

php

symfony