如何从 javascript 中的对象中删除时间？

Question

我正在尝试从我的对象中的属性之一中删除时间。实际上我检查：索引，如果时间戳存在于属性值中。其实我有这个

输入

[
  {
    "S": "Charge Interest Against Past Due Account",
    "C": "Mon Apr 13 10:38:05 GMT 2015"
  },
  {
    "S": "Charge Interest Against Past Due Account",
    "C": "Mon Apr 13 10:35:05 GMT 2015"
  }
]

产出

[
  {
    "S": "Charge Interest Against Past Due Account",
    "C": "Mon Apr 13  2015"
  },
  {
    "S": "Charge Interest Against Past Due Account",
    "C": "Mon Apr 13  2015"
  }
]

Javascript

var object = ary.map(function(o){
    var result={}
   // console.log(o)
    for(i in o){
        console.log(i+":"+o[i]) ;
        if(o[i].indexOf(":")!=-1){
            console.log("timestam present")
        }
    }
})

原始数组保持不变，结果应该在单独的数组中捕获。

这里是 link 到 fiddle.

Answer 1

您可以将 C 属性拆分为 space，然后重新加入您想要保留的部分。试试这个：

for (var i = 0; i < ary.length; i++) {
    var dateValues = ary[i].C.split(' ');
    ary[i].C = dateValues[0] + ' ' + dateValues[1] + ' ' + dateValues[2] + ' ' + dateValues[5]    
};

Updated fiddle

没有丑陋的字符串连接的替代方案：

for (var i = 0; i < ary.length; i++) {
    var dateValues = ary[i].C.split(' ')
    dateValues.splice(3, 2);
    ary[i].C = dateValues.join(' ');   
};

Answer 2

var ary = [
{
"S": "Charge Interest Against Past Due Account",
"C": "Mon Apr 13 10:38:05 GMT 2015"
},
{
"S": "Charge Interest Against Past Due Account",
"C": "Mon Apr 13 10:35:05 GMT 2015"
}];
for (var i = 0; i < ary.length; i++) {
    ary[i].C = ary[i].C.replace(/\d+:\d+:\d+\s*GMT\s*/g, '');
}
console.info(ary);

Answer 3

最好的办法是将日期解析为 Date 对象，然后重新格式化它。您可以随心所欲地格式化它，有或没有时间。有许多库可用于格式化日期。您声明您正在使用 jQuery，有一个日期格式插件。

我不建议您尝试将字符串分解成片段。有许多日期格式（您不指定此日期的来源）并且您的解决方案将来很容易停止工作。

Answer 4

var ary=[
  {
    "S": "Charge Interest Against Past Due Account",
    "C": "Mon Apr 13 10:38:05 GMT 2015"
  },
  {
    "S": "Charge Interest Against Past Due Account",
    "C": "Mon Apr 13 10:35:05 GMT 2015"
  }]

ary.map(function(o){
        var d = new Date(o.C);
        o.C = d.toDateString();
})
console.dir(ary)

输出

C: "Mon Apr 13 2015"
S: "Charge Interest Against Past Due Account"

C: "Mon Apr 13 2015"
S: "Charge Interest Against Past Due Account"

更新

要保留原始对象并在其他对象中获取结果，请使用以下代码。

var ary=[
  {
    "S": "Charge Interest Against Past Due Account",
    "C": "Mon Apr 13 10:38:05 GMT 2015"
  },
  {
    "S": "Charge Interest Against Past Due Account",
    "C": "Mon Apr 13 10:35:05 GMT 2015"
  }]

var a = ary.map(function(o){
        var result = {};
        var d = new Date(o.C);
        result.S = o.S;
        result.C = d.toDateString();
        return result;
})
console.dir(a)

如何从 javascript 中的对象中删除时间？

How to remove time from object in javascript?

javascript

arrays

jquery

datetime

properties