在正则表达式匹配处断句并使用 javascript 创建数组

Question

我有一个包含多项选择题和答案的字符串，如下所示：

(1) Capital of Bangladesh is-
(A) Dhaka (B) Rangpur (C) Chittagong (D) Comilla। Ans (A) Dhaka
(2) Largest city of Bangladesh is-
(A) Mirpur (B) Rangpur (C) Chittagong (D) Comilla। Ans (C) Chittagong
(3) Smallest city of Bangladesh is-
(A) Dhaka (B) Rangpur (C) Chittagong (D) Meherpur। Ans (B) Rangpur

我需要根据上面的字符串创建 json，以便它创建单独的问题和答案

最后的 json 会是这样的：

{"questions":
    [
     {
    "options":["Dhaka","Rangpur","Chittagong","Comilla"],
    "body":"Capital of Bangladesh is-",
    "answers":["A"]

    },
    {
     "options":["Mirpur","Rangpur","Chittagong","Comilla"],
    "body":"Capital of Bangladesh is-",
    "answers":["C"]
}   
    ]
}

我试过

   var result = reader.result.split('\n');
    for (var index = 0; index < result.length; index++) {
      var question = result[index]
      if(question.match("/[(/)]/g")){
        questions.push = question
      }
      else {
        questions.push = question
      }
    }
    console.log(questions)

我怎样才能做到

Answer 1

试一试

我们需要 /u 来处理 unicode 然后 .+ 而不是 \w 因为双字节

使用 Unicode 正则表达式的更多内容

Regular expression \p{L} and \p{N}

const str = `(1) The main language of Bangladesh is-
(ক) বাংলা (খ) ইংরেজি  (C) Hindi (D) French। Ans (ক) বাংলা
(2) Largest city of Bangladesh is-
(A) Mirpur (B) Rangpur (C) Chittagong (D) Comilla। Ans (C) Chittagong
(3) Smallest city of Bangladesh is-
(A) Dhaka (B) Rangpur (C) Chittagong (D) Meherpur। Ans (B) Rangpur`;

const obj = str.split(/\n/u).reduce((acc,line,i) => { 
  if (i%2===0) acc.questions.push({"body":line.match(/\(.+\) (.*)/u)[1]}); // remove the (X) from the question
  else {
    const curItem = acc.questions[acc.questions.length-1]; // last pushed object
    let [optionStr,answer] = line.split(/। /u);// split on this special character
    // assuming 4 options 
    curItem.options = optionStr
      .match(/\(.+\) (.+) \(.+\) (.+) \(.+\) (.+) \(.+\) (.+)/u)
      .slice(1); // drop the first element from the result (full match)
    answer = answer.match(/\((.+)\)/u)[1]; // just get the letter from the bracket
    curItem.answers = [answer];
  }  
  return acc
},{questions:[]})

console.log(obj)

Answer 2

您还可以使用模式来获取捕获组中的问答部分。然后对于答案部分，您可以在括号之间拆分大写字符。

带捕获组的模式：

^\(\d+\) (.+)\n(\([A-Z]\).*?)। Ans \(([A-Z])\)

^ 字符串开头
\(\d+\) 匹配括号和 space
(.+)\n 捕获 组 1，匹配行的其余部分和换行符
(\([A-Z]\).*?) 捕获 组 2，匹配括号之间的大写字符，后跟尽可能少的字符
। Ans 字面匹配
\(([A-Z])\) 在 组 3

Regex demo

或使用 unicode categories 如果支持：

^\(\p{Nd}\)\s+(.+)\n(\(\p{L}\).*?)।\s+Ans\s+\((\p{L})\)

Regex demo

代码中第1组的值用i[1]等表示。

const str = `(1) Capital of Bangladesh is-
(A) Dhaka (B) Rangpur (C) Chittagong (D) Comilla। Ans (A) Dhaka
(2) Largest city of Bangladesh is-
(A) Mirpur (B) Rangpur (C) Chittagong (D) Comilla। Ans (C) Chittagong
(3) Smallest city of Bangladesh is-
(ক) বাংলা (খ) ইংরেজি । Ans (B) Rangpur`;
const regex = /^\(\p{Nd}+\)\s+(.+)\n(\(\p{L}\).*?)।\s+Ans\s+\((\p{L})\)/gum;

let result = {
  questions: Array.from(str.matchAll(regex)).map(i =>
    ({
      options: i[2].split(/\s*\(\p{L}\)\s*/u).filter(Boolean),
      body: i[1],
      answers: [i[3]]
    })
  )
};

console.log(result);

或者使用否定字符类 [^()]+ 来匹配括号之间的内容的示例。

const str = `(1) Capital of Bangladesh is-
(A) Dhaka (B) Rangpur (C) Chittagong (D) Comilla। Ans (A) Dhaka
(2) Largest city of Bangladesh is-
(A) Mirpur (B) Rangpur (C) Chittagong (D) Comilla। Ans (C) Chittagong
(3) Smallest city of Bangladesh is-
(ক) বাংলা (খ) ইংরেজি । Ans (B) Rangpur`;
const regex = /^\([^()]+\)\s+(.+)\n(\([^()]+\).*?)।\s+Ans\s+\(([^()]+)\)/gm;

let result = {
  questions: Array.from(str.matchAll(regex)).map(i =>
    ({
      options: i[2].split(/\s*\([^()]+\)\s*/).filter(Boolean),
      body: i[1],
      answers: [i[3]]
    })
  )
};

console.log(result);

在正则表达式匹配处断句并使用 javascript 创建数组

Break sentence at regex match and create array using javascript

javascript

regex

pattern-matching