swift 将文本字段输入范围编号设置为 17 - 100

swift set textfield input range number between 17 - 100

所以我制作了一个包含用户输入的一堆数据的表单,输入的是年龄,我希望用户只输入 17 - 100 之间的数据。

之后我有了这个包含每个文本字段验证的函数,所以如果验证正确,它将使按钮启用

这是我的验证函数:

func buttonReady() {
    
    if umurTextField.text != "" && domisiliTextField.text != "" && rencanaPembelianTextField.text != "" && luasTanahTextField.text != "" && luasBangunanTextField.text != "" && budgetTextField.text != "" && metodePembayaranTextField.text != "" && lantaiRumahTextField.text != "" {
        ButtonSearch.isEnabled = true
        ButtonSearch.backgroundColor = #colorLiteral(red: 0.5176470588, green: 0.3294117647, blue: 0.1333333333, alpha: 1)
        ButtonSearch.setTitleColor(#colorLiteral(red: 1.0, green: 1.0, blue: 1.0, alpha: 1.0), for: .normal)
        ButtonSearch.layer.cornerRadius = 25
    }else {
        ButtonSearch.isEnabled = false
        ButtonSearch.setTitleColor(#colorLiteral(red: 1, green: 1, blue: 1, alpha: 1), for: .normal)
        ButtonSearch.layer.cornerRadius = 25
        ButtonSearch.layer.backgroundColor = #colorLiteral(red: 0.6666666667, green: 0.4745098039, blue: 0.2588235294, alpha: 0.4408410685)
    }
}

到目前为止,我只是将验证设置为不为空,但我想将“umurTextField”验证设置为仅在 17 - 100 之间,我该怎么做?

谢谢

可能是

if let res = umurTextField.text , 
   let value = Int(res), 
   (17...100).contains(value) , .......... {

}

您可以使用

测试它是否在范围内
17...100 ~= Int(umurTextField.text) ?? .min

示例

for test in ["8", "34", "b", "99", "104"] {
    print("\(test): \(17...100 ~= Int(test) ?? .min)")
}

8: false
34: true
b: false
99: true
104: false