zip 输出中值的数量不正确？

Question

我一直在研究一个问题，涉及取多个数字对，并创建某种形式的求和循环，将每对数字加在一起。

我没有得到正确数量的输出，例如输入了15对数字，结果只有8对。

到目前为止，这是我的代码...

data = "917128 607663\
907859 281478\
880236 180499\
138147 764933\
120281 410091\
27737 932325\
540724 934920\
428397 637913\
879249 469640\
104749 325216\
113555 304966\
941166 925887\
46286 299745\
319716 662161\
853092 455361"

data_list = data.split(" ") # creating a list of strings

data_list_numbers = [] # converting list of strings to list of integers 
for d in data_list:
    data_list_numbers.append(int(d))

#splitting the lists into two with every other integer (basically to get the pairs again.
list_one = data_list_numbers[::2]   
list_two = data_list_numbers[1::2]

zipped_list = zip(list_one, list_two) #zipping lists 

sum = [x+y for x,y in zip(list_one, list_two)] # finding the sum of each pair

print(sum)

我错过了什么？

Answer 1

像这样引用输入字符串："""..."""，删除反斜杠，并使用 re.split 在空格处拆分。请注意，像您一样使用不带空格的反斜杠会导致 data 中的数字相互碰撞。也就是这个：

"607663\
907859"

等同于："607663907859".

import re

data = """917128 607663
907859 281478
880236 180499
138147 764933
120281 410091
27737 932325
540724 934920
428397 637913
879249 469640
104749 325216
113555 304966
941166 925887
46286 299745
319716 662161
853092 455361"""

data_list = re.split(r'\s+', data) # creating a list of strings

data_list_numbers = [] # converting list of strings to list of integers 
for d in data_list:
    data_list_numbers.append(int(d))

#splitting the lists into two with every other integer (basically to get the pairs again.
list_one = data_list_numbers[::2]   
list_two = data_list_numbers[1::2]

zipped_list = zip(list_one, list_two) #zipping lists 

sum = [x+y for x,y in zip(list_one, list_two)] # finding the sum of each pair

print(sum)
# [1524791, 1189337, 1060735, 903080, 530372, 960062, 1475644, 1066310, 1348889, 429965, 418521, 1867053, 346031, 981877, 1308453]

zip 输出中值的数量不正确？

Incorrect number of values in output from zip?

python

loops

sum