将 NA 替换为 0 的 SSRS 表达式

SSRS Expression to Substitute 0 for NA

我有下面提供的 SSRS 表达式。该表达式的问题在于,当第一列的值为 NA 时,最后一列有时会显示 #VALUE!。基本上是计算失败
我怎样才能修复这个表达式以使其显示正确的数值?一种可能的解决方案是用 0 代替 NA,但我该如何实现呢?

表达式:

=iif(Fields!NumType.Value = "1",iif(reportItems!txt_Current_Filing_Firm.value = "","0",reportItems!txt_Current_Filing_Firm.value),"1") - IIF(Fields!NumType.Value = "1",iif(reportitems!txt_Compare_Filing_Firm.value = "","0",reportitems!txt_Compare_Filing_Firm.value),"1")

SSRS 中的当前输出:

Column 1 | Column 2 |  Column 3

NA          3456.00    #VALUE!
NA        347856.00    #VALUE!
NA      98763456.00    #VALUE!
NA         33456.35    #VALUE!

SSRS 中的预期输出:

Column 1 | Column 2 |  Column 3

0          3456.00    -3456.00
0        347856.00    -347856.00
0      98763456.00    -98763456.00
0         33456.35    -33456.35

这是解决方案。思想分享。我们需要将 "NA" 替换为 0。有效!

=iif(字段!NumType.Value = "1",iif(reportItems!txt_Current_Filing_Firm.value = "" 或 reportItems!txt_Current_Filing_Firm.value = "NA","0" ,reportItems!txt_Current_Filing_Firm.value),"1") - IIF(Fields!NumType.Value = "1",iif(reportItems!txt_Current_Filing_Firm.value = "" OR reportitems!txt_Compare_Filing_Firm.value = "NA","0",报告项目!txt_Compare_Filing_Firm.value),"1")