Python 中原始列表中特定项目的子列表提取
Sublists Extraction in Python on a specific item in original list
问题
如何从列表中提取子列表，每个子列表的上下边缘是列表中的特定项。
示例 1
输入
Sublist_Slicing_edge = 0
我的列表 = [0,1,0,1,-1,-1,-2,1,2,3,4,0]
期望的输出
list1 = [0,1,0]
list2 = [0,1,-1,-1,-2,1,2,3,4,0]
示例 2
输入
Sublist_Slicing_edge = "我"
mylist = [“我”，“我”，“一个”，“工程师”，“和”，“我”，“我”，“也”，“一个”，“科学家”，”！ ","但是","我","是","不是","a","数学家"]
期望的输出
list1 = ["我", "我", "一个", "工程师", "和", "我"]
list2 = ["我", "我", "也是","a", "科学家","!","但是","我"]
解决方案需要您执行以下步骤：
查找列表中特定项目的索引位置
根据步骤 1 中找到的索引位置对主列表进行切片
查找元素在列表中的索引位置
>>> mylist = ["I" , "am" , "an" , "Engineer" , "and" , "I" , "am", "also","a" , "Scientist","!","But","I","am","not","a","Mathmatician"]
>>> sublist_str = "I"
>>> indexes_list = [i for i,v in enumerate(mylist) if v == sublist_str]
>>> indexes_list
[0, 5, 12]
- 正在使用索引位置创建子列表：
>>> [mylist[indexes_list[i]:indexes_list[i+1]+1] for i in range(len(indexes_list)-1)]
[['I', 'am', 'an', 'Engineer', 'and', 'I'], ['I', 'am', 'also', 'a', 'Scientist', '!', 'But', 'I']]
问题
如何从列表中提取子列表，每个子列表的上下边缘是列表中的特定项。
示例 1
输入
Sublist_Slicing_edge = 0
我的列表 = [0,1,0,1,-1,-1,-2,1,2,3,4,0]
期望的输出
list1 = [0,1,0]
list2 = [0,1,-1,-1,-2,1,2,3,4,0]
示例 2
输入
Sublist_Slicing_edge = "我"
mylist = [“我”，“我”，“一个”，“工程师”，“和”，“我”，“我”，“也”，“一个”，“科学家”，”！ ","但是","我","是","不是","a","数学家"]
期望的输出
list1 = ["我", "我", "一个", "工程师", "和", "我"]
list2 = ["我", "我", "也是","a", "科学家","!","但是","我"]
解决方案需要您执行以下步骤：
查找列表中特定项目的索引位置
根据步骤 1 中找到的索引位置对主列表进行切片
查找元素在列表中的索引位置
>>> mylist = ["I" , "am" , "an" , "Engineer" , "and" , "I" , "am", "also","a" , "Scientist","!","But","I","am","not","a","Mathmatician"]
>>> sublist_str = "I"
>>> indexes_list = [i for i,v in enumerate(mylist) if v == sublist_str]
>>> indexes_list
[0, 5, 12]
- 正在使用索引位置创建子列表：
>>> [mylist[indexes_list[i]:indexes_list[i+1]+1] for i in range(len(indexes_list)-1)]
[['I', 'am', 'an', 'Engineer', 'and', 'I'], ['I', 'am', 'also', 'a', 'Scientist', '!', 'But', 'I']]