RestTemplate - 如何以正确的方式显示 HttpServerErrorException - 异常（RestClientException、HttpStatusCodeException）

Question

在客户端，我使用 RestTemplate 的 exchange 方法进行 RestFul 网络服务调用。服务调用位于 try/catch block。当响应代码为 2xx 时一切正常。

我有一个看起来像这样的 catch 块：

catch (HttpServerErrorException e) {
            String msg = String.format(
                    "Error getting book data for bookId: %s and author: %s",
                    bookId,
                    author.name,
                    e.getStatusCode(),
                    e.getResponseBodyAsString());
            LOGGER.error(msg);
        }

我想 throw new HttpServerErrorException() 并显示所有需要的字段以供前端开发人员显示它。

我知道我应该做类似 throw new HttpServerErrorException()

的事情

我不知道该怎么做，感谢任何帮助！

Answer 1

您可以创建一个 HttpException class，其中格式在前端是已知的。当您在前端获得非 200 状态代码时，您可以将响应主体序列化为 json，然后从那里提取相关信息。

public class HttpException {
    private int statusCode;
    public String message;

    public int getStatusCode() {
        return statusCode;
    }

    public void setStatusCode(int statusCode) {
        this.statusCode = statusCode;
    }
}

Answer 2

我找到了一个可行的解决方案，那就是将错误处理集中在一个地方，您可以为此使用一个 @RestControllerAdvice 注释 class.

这是我添加的：

CustomizedResponseEntityExceptionHandler.java

@ControllerAdvice
@RestController
public class CustomizedResponseEntityExceptionHandler extends ResponseEntityExceptionHandler {

    @ExceptionHandler(Exception.class)
    protected ResponseEntity<Object> handleAllExceptions(Exception ex, WebRequest request) {
        ExceptionResponse exceptionResponse =
                new ExceptionResponse(new Date(), ex.getMessage(),
                        request.getDescription(false));

        return new ResponseEntity<>(exceptionResponse, HttpStatus.INTERNAL_SERVER_ERROR);
    }

    @ExceptionHandler(NotFoundException.class)
    protected ResponseEntity<Object> handleUserNotFoundException(NotFoundException ex, WebRequest request) {
        ExceptionResponse exceptionResponse =
                new ExceptionResponse(new Date(), ex.getMessage(),
                        request.getDescription(false));

        return new ResponseEntity<>(exceptionResponse, HttpStatus.NOT_FOUND);
    }
}

ExceptionResponse.java

public class ExceptionResponse {

    private Date timestamp;
    private String message;
    private String details;

    public ExceptionResponse(Date timestamp, String message, String details) {
        this.timestamp = timestamp;
        this.message = message;
        this.details = details;
    }
}

NotFoundException.java

@ResponseStatus(HttpStatus.NOT_FOUND)
public class NotFoundException extends RuntimeException {
    public NotFoundException(String message) {
        super(message);
    }
}

在 catch 块中，我实现了两个可行的解决方案。

第一个解决方案： 使用 HttpServerErrorException class

第二种解决方案：使用自定义class

 catch (HttpServerErrorException e) {
                String msg = String.format(
                        "Error getting book data for bookId: %s and author: %s",
                        bookId,
                        author.name,
                        e.getStatusCode(),
                        e.getResponseBodyAsString());
                LOGGER.error(msg);
//Second solution: throw new NotFoundException("Book with id: " + bookId + " and author " + author.name + " doesn't exist.");
//First solution:  throw new HttpServerErrorException(e.getStatusCode(), msg);

}

RestTemplate - 如何以正确的方式显示 HttpServerErrorException - 异常（RestClientException、HttpStatusCodeException）

RestTemplate - How to display HttpServerErrorException in right way - Exceptions (RestClientException, HttpStatusCodeException)

java

exception

try-catch