如何在 Oracle 中获得正确的总和结果

Question

我正在使用子查询来计算别名的总和，但似乎 return 结果错误

我的table:

itm_code          itm_name            PACKING_STYLE       TOTAL_QUANTITY

3211483       DEODORIZATION              1                      32
3211484       DEODORIZATION FILTER       1                      20
3211485       FILTER                     30                     30
3211486       FILTER-RO 8INCH(S)         30                     30

这是我的食谱：

1. Full box = Integer of(total qty/ packing style)

2. Spare_box: via spare_quantity
   spare_quantity = total_quantity - full_box * packing_style.
   If spare_quantity = 0 => spare_box = 0
   If spare_quantity  > 0 => spare_box = 1

这是我的查询：

    SELECT 
         l48.itm_code itmcd
         , l48.itm_name itmname
         , l48.PACKING_STYLE
         , l48.TOTAL_QUANTITY             
         , FULLBOX
         , SPARE_BOX
                    
         , SUM(FULLBOX + SPARE_BOX) AS TOTALBOX 
      from 
         log0048d l48
         , ( SELECT 
                
                ROUND(SUM(l48.TOTAL_QUANTITY / l48.PACKING_STYLE)) AS FULLBOX
                , CASE WHEN ROUND(SUM(l48.TOTAL_QUANTITY - (l48.TOTAL_QUANTITY/l48.PACKING_STYLE) * l48.PACKING_STYLE)) =  0 THEN  0
                       WHEN ROUND(SUM(l48.TOTAL_QUANTITY - (l48.TOTAL_QUANTITY/l48.PACKING_STYLE) * l48.PACKING_STYLE)) >  0 THEN  1
                   END AS SPARE_BOX
            FROM log0048d l48 )
         
     where 1 = 1
       AND l48.reqst_no  = 'SMO21071900398'         
      GROUP BY 
    
        l48.itm_code
        , l48.itm_name
        , l48.reqst_no_itm   
        , l48.PACKING_STYLE
        , l48.TOTAL_QUANTITY             
        , FULLBOX
        , SPARE_BOX

然后我收到的错误是：

itm_code        itm_name      PACKING_STYLE  TOTAL_QUANTITY    FULLBOX    SPAREBOX    TOTALBOX

3211483     DEODORIZATION           1             32             58          0           58
3211484     DEODORIZATION FILTER    1             20             58          0           58
3211485     FILTER                  30            30             58          0           58
3211486     FILTER-RO 8INCH(S)      30            30             58          0           58

我预期的正确结果如下：

itm_code        itm_name      PACKING_STYLE  TOTAL_QUANTITY    FULLBOX    SPAREBOX    TOTALBOX

3211483     DEODORIZATION           1             32             32          0           32
3211484     DEODORIZATION FILTER    1             20             20          0           20
3211485     FILTER                  30            30             1           0           1
3211486     FILTER-RO 8INCH(S)      30            30             1           0           1

我怎样才能得到我预期的正确结果？

Answer 1

要么你的示例数据不完整，要么我没有得到你的要求，但是

select 
  code, 
  name, 
  packing_style, 
  total_quantity, 
  floor(total_quantity / packing_style) as fullbox, 
  sign(total_quantity - floor(total_quantity / packing_style) * packing_style) as sparebox,
  floor(total_quantity / packing_style) + sign(total_quantity - floor(total_quantity / packing_style) * packing_style) as totalbox 
from thetable

应该完成这项工作。不需要分组（尤其是不是按结果的几乎每一列分组，这样的分组有什么意义）

当然你可以让它更具可读性和更好的可维护性，例如如下

with 

fbe(code, fullbox) as (
  select 
    code, 
    floor(total_quantity / packing_style) as fullbox
  from thetable
),

sbe(code, sparebox) as (
  select
    t.code,
    sign(t.total_quantity - fbe.fullbox * t.packing_style) as sparebox
  from thetable t inner join fbe on t.code = fbe.code
)

select 
  t.code,
  t.name,
  t.packing_style,
  t.total_quantity,
  fbe.fullbox,
  sbe.sparebox,
  fbe.fullbox + sbe.sparebox as totalbox
from thetable t 
  inner join fbe on t.code = fbe.code 
  inner join sbe on t.code = sbe.code

您还可以通过取模运算得到 sparebox 的值，即如果 total_quantity/packing_style 的余数与 0 不同，您需要一个备用箱，否则您不需要.也就是说，您也可以按如下方式编写查询：

select 
  code, 
  name, 
  packing_style, 
  total_quantity, 
  floor(total_quantity / packing_style) as fullbox, 
  sign(mod(total_quantity / packing_style)) as sparebox,
  floor(total_quantity / packing_style) + sign(mod(total_quantity/ packing_style)) as totalbox 
from thetable

此外，totalbox 将始终是 fullbox（如果总数量是包装样式的倍数）或 fullbox + 1（否则），因此您可以进一步简化为如下：

select 
  code, 
  name, 
  packing_style, 
  total_quantity, 
  floor(total_quantity / packing_style) as fullbox, 
  sign(mod(total_quantity / packing_style)) as sparebox,
  ceil(total_quantity / packing_style) as totalbox 
from thetable

请参阅 floor, ceil, sign and mod

的文档

如何在 Oracle 中获得正确的总和结果

How to get correct result in sum in Oracle

sql

oracle

oracle11g