如何比较python中两个不同编码的字符串？

Question

上下文：

我正在从 'utf-8', application_name = 'MicrosoftEdge'

编码的 txt 文件中提取字符串

然后我使用 python ctypes 模块来确定当前活动的应用程序 window = curr_application

user32 = ctypes.WinDLL('user32', use_last_error=True)
curr_window = user32.GetForegroundWindow()
window_name = str(win32gui.GetWindowText(curr_window))
rev = window_name[::-1]
pos = rev.find("-")
curr_application = rev[0:pos][::-1].replace(" ","")

这也是 returns：'MicrosoftEdge'

但当我这样做时：

print(curr_application == application_name)

总是returnsFalse

这是我从中得到的输出：

>>> print(application_name.encode())
b'MicrosoftEdge\n'
>>> print(curr_application.encode())
b'Microsoft\xe2\x80\x8bEdge'

我的问题是，我应该怎么做才能在比较两个字符串时得到 true？

Answer 1

更新：

以下是对我有用的方法：

import string
allowed_chars = string.ascii_letters
application_name = 'MicrosoftEdge'
curr_application = 'Microsoft\xe2\x80\x8bEdge'
application = ""
for letter in curr_application:
    if letter in allowed_chars:
        application = application + letter
print(application==application_name)

然后 returns True

Answer 2

您可以通过将其替换为空字符串来删除该字符：

curr_application.replace('\N{ZERO WIDTH SPACE}', '')

如何比较python中两个不同编码的字符串？

How to compare two strings of different encoding in python?

python

string

encoding

ctypes