如何获取每年的点名和最大值？ (SQL)

Question

到目前为止这是我的代码它在 T-SQL.

我无法添加 driver_name 列。我应该使用哪种聚合？

SELECT MAX(race_points) max_points, year, driver_name
FROM 

    (SELECT

        CONCAT(forename,' ',surname) AS driver_name,
        year,
        (CONVERT(FLOAT,points)) AS race_points     
     
    FROM 
            results AS r

            INNER JOIN constructors AS c
            ON r.constructorId = c.constructorId

            INNER JOIN drivers AS d
            ON r.driverId = d.driverId

            INNER JOIN races AS rc
            ON r.raceId = rc.raceId) AS sub
GROUP BY year;

这就是 sub 的样子

driver_name	year	race_points
a	2010	2
a	2011	3
b	2011	4
b	2012	3
c	2012	4

我想让它看起来像是在撒谎

driver_name	year	max_points
a	2010	2
b	2011	4
c	2012	4

任何帮助将不胜感激。

Answer 1

使用 row_number()，您可以根据对数字进行分区的方式来指定行号。如果相应地对其进行排序，则可以 select 每组中的第 1 行。

WITH cte as
(
   SELECT
     CONCAT(forename,' ',surname) AS driver_name,
     year,
     (CONVERT(FLOAT,points)) AS race_points,
     row_number() over (partition by year order by (CONVERT(FLOAT,points)) desc) as rn     
   FROM 
     results AS r    
     INNER JOIN constructors AS c ON r.constructorId = c.constructorId
     INNER JOIN drivers AS d ON r.driverId = d.driverId
     INNER JOIN races AS rc ON r.raceId = rc.raceId
)
SELECT * FROM cte 
WHERE rn = 1

如何获取每年的点名和最大值？ (SQL)

How to get the name and maximum values of points for each year? (SQL)

sql

sql-server

group-by

aggregate-functions