如何获取每年的点名和最大总和值？

Question

到目前为止，这是我的代码。它在 T-SQL.

但是，它只选择每年有最大值的项目，而不是总分。

WITH cte as
(
   SELECT
     CONCAT(forename,' ',surname) AS driver_name,
     year,
     (CONVERT(FLOAT,points)) AS race_points,
     row_number() over (partition by year order by (CONVERT(FLOAT,points)) desc) as rn     
   FROM 
     results AS r    
     INNER JOIN constructors AS c ON r.constructorId = c.constructorId
     INNER JOIN drivers AS d ON r.driverId = d.driverId
     INNER JOIN races AS rc ON r.raceId = rc.raceId
)
SELECT * FROM cte 
WHERE rn = 1

这就是 sub 的样子

driver_name	year	race_points
a	2011	1
a	2011	1
b	2011	2
b	2011	2
c	2012	3
c	2012	3
d	2012	4
d	2012	4

我正在尝试让它看起来像这样

driver_name	year	max_points
b	2011	4
d	2012	8

我目前得到的是这个

driver_name	year	max_points
b	2011	2
d	2012	4

任何帮助将不胜感激。

Answer 1

您想要使用 window 函数进行聚合：

WITH cte as (
      SELECT CONCAT(forename, ' ', surname) AS driver_name,
             year, SUM(points) as race_points,
             RANK() OVER (PARTITION BY year ORDER BY SUM(points) DESC) as seqnum
      FROM results r JOIN 
           constructors c
           ON r.constructorId = c.constructorId JOIN
           drivers d
           ON r.driverId = d.driverId JOIN
           races rc
           ON r.raceId = rc.raceId
      GROUP BY CONCAT(forename, ' ', surname), year
     )
SELECT *
FROM cte
WHERE seqnum = 1;

如何获取每年的点名和最大总和值？

How to get the name and maximum sum values of points for each year?

sql

sql-server

aggregate-functions

common-table-expression