如何生成 2 个值之间的值？

Question

我的数据如下所示

with test(col) as (
    select  '01-06' from dual union all
    select  '45-52' from dual
    ) select col from test ;

需要OP

COL
01
02
.
.
.
06
45
46
.
.
52

其实我的table数是2万。我用connect by 但是速度很慢。

Answer 1

您可以使用递归查询生成值：

with test(col) as (
    select  '01-06' from dual union all
    select  '45-52' from dual
), bounds (l,u) as (
  select to_number(substr(col,1,2)), to_number(substr(col,4,2)) from test
), r (l,u) as (
  select l,u from bounds
  union all
  select r.l + 1, r.u from r where r.l < r.u
)
select to_char(l,'00') from r order by l;

（如果任何值不是 2 位数字，则适当编辑 substr 表达式）

Answer 2

说“我使用 connect by 但它很慢”而不发布您编写的代码并没有多大帮助。我假设你做错了，即有太多重复值导致速度变慢。看看这个 connect by 选项是否有帮助。

SQL> with test (col)
  2  as
  3    (select '1-6' from dual
  4     union all
  5     select '45-52' from dual
  6    )
  7  select lpad(to_number(substr(col, 1, instr(col, '-') - 1)) + column_value - 1, 2, '0') val
  8  from test cross join
  9    table(cast(multiset(select level from dual
 10                        connect by level <= to_number(substr(col, instr(col, '-') + 1)) -
 11                                            to_number(substr(col, 1, instr(col, '-') - 1)) + 1
 12                       ) as sys.odcinumberlist));

VAL
---
01
02
03
04
05
06
45
46
47
48
49
50
51
52

14 rows selected.

SQL>

如何生成 2 个值之间的值？

How to generate values between 2 values?

sql

oracle

oracle11g