如何获得多个参数的计数和求和以防万一

Question

我在 MySQL（版本 - 5.7.18-log）中有以下 table。

ID      Old_Date       Curr_Date             Status       Price       items
ID-1    2021-07-14     2021-09-30 13:15:15   Done         1500        3
ID-1    2021-06-26     2021-09-30 13:15:15   Hold         3500        6
ID-1    2021-05-26     2021-09-30 13:15:15   In Progress  4500        1
ID-1    2021-03-04     2021-09-30 13:15:15   Done         5000        3
ID-1    2021-01-11     2021-09-30 13:15:15   Done         2800        2

根据上面的table，我需要获取最近 1、6 和 9 个月时间间隔内状态为 Done 和 Hold 的实例的计数和总和.

需要在Old_Date和Curr_Date之间计算间隔。

需要输出-

ID     1_Month_Count  6_Month_Count  9_Month_Count   1_Month_Sum  6_Month_Sum  9_Month_Sum
ID-1   0              2              4               0            5000         12800

我尝试了以下查询，但它不起作用。

SELECT ID,
SUM(CASE WHEN TIMESTAMPDIFF(month, Old_Date, Curr_Date) <= 12  
WHEN (Status IN ('Done', 'Hold') THEN SUM(ID) ELSE 0 END) AS 12_Month_Done`,
FROM Table
Group BY ID;

Answer 1

我认为存储过程是实现这一目标的一种方式。在此过程中，您必须针对 1、6 和 9 个月进行 3 次查询。喜欢

SELECT COUNT(ID) as cnt_id, SUM(price) as sum_price INTO 1_month_count, 1_month_sum WHERE status = 'Hold' OR status = 'Done' AND TIMESTAMPDIFF(MONTH, old_date, curr_date) >= 1 AND  TIMESTAMPDIFF(MONTH, old_date, curr_date) < 6;

然后你 return 你的变量 1_month_count 等等

SELECT @1_month_count, @1_month_sum; /*and all others*/

有关带有 OUT 参数的存储过程的更多信息，请参见此处： https://dev.mysql.com/doc/refman/8.0/en/create-procedure.html

Answer 2

如果您只想在结果中找到符合条件的 ID，则在过滤 table:

后使用条件聚合

SELECT ID,
       COUNT(CASE WHEN Old_Date >= Curr_Date - INTERVAL 1 month THEN 1 END) AS `1_Month_Count`,
       COUNT(CASE WHEN Old_Date >= Curr_Date - INTERVAL 6 month THEN 1 END) AS `6_Month_Count`,
       COUNT(*) AS `9_Month_Count`, 
       SUM(CASE WHEN Old_Date >= Curr_Date - INTERVAL 1 month THEN Price ELSE 0 END) AS `1_Month_Sum`,
       SUM(CASE WHEN Old_Date >= Curr_Date - INTERVAL 6 month THEN Price ELSE 0 END) AS `6_Month_Sum`,
       SUM(Price) AS `9_Month_Sum`            
FROM tablename
WHERE Status IN ('Done', 'Hold') AND Old_Date >= Curr_Date - INTERVAL 9 month
GROUP BY ID;

如果您想要所有 ID，即使它们不符合条件：

SELECT ID,
       COUNT(CASE WHEN Old_Date >= Curr_Date - INTERVAL 1 month 
            AND Status IN ('Done', 'Hold') THEN 1 END) AS `1_Month_Count`,
       COUNT(CASE WHEN Old_Date >= Curr_Date - INTERVAL 6 month 
            AND Status IN ('Done', 'Hold') THEN 1 END) AS `6_Month_Count`,
       COUNT(CASE WHEN Old_Date >= Curr_Date - INTERVAL 9 month 
            AND Status IN ('Done', 'Hold') THEN 1 END) AS `9_Month_Count`, 
       SUM(CASE WHEN Old_Date >= Curr_Date - INTERVAL 1 month 
            AND Status IN ('Done', 'Hold') THEN Price ELSE 0 END) AS `1_Month_Sum`,
       SUM(CASE WHEN Old_Date >= Curr_Date - INTERVAL 6 month 
            AND Status IN ('Done', 'Hold') THEN Price ELSE 0 END) AS `6_Month_Sum`,
       SUM(CASE WHEN Old_Date >= Curr_Date - INTERVAL 9 month 
            AND Status IN ('Done', 'Hold') THEN Price ELSE 0 END) AS `9_Month_Sum`            
FROM tablename
GROUP BY ID;

参见demo。

如何获得多个参数的计数和求和以防万一

How to get count and sum with multiple parameter in case when

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