使用模型字段一起获取 Django 模型中的多对多字段

Question

我有两个模型；

class userPageAuths(models.Model):

    enName = models.CharField(max_length=30)
    trName = models.CharField(max_length=30)

    def __str__(self):
        return self.enName

class userPages(models.Model):

    enName = models.CharField(max_length=30)
    trName = models.CharField(max_length=30)
    parent_id = models.IntegerField(blank=True, null=True)
    user_page_auths = models.ManyToManyField(userPageAuths, related_name="page_auth_list", blank=True)

    def __str__(self):
        return self.enName

第一个模型数据在我的数据库中；

第二个模型数据是；

此数据适用于多对多字段；

我想得到这样的所有数据；

[
    {
        "id": 1,
        "enName": "x",
        "trName": "x",
        "parent_id": null
    },
    {
        "id": 2,
        "enName": "y",
        "trName": "y",
        "parent_id": null
    },
    {
        "id": 3,
        "enName": "z",
        "trName": "z",
        "parent_id": 2
    },
    {
        "id": 1,
        "enName": "a",
        "trName": "a",
        "parent_id": 3 // this userpages_id which connected manytomany relation and ı want to get this as a parent_id
    },
    {
        "id": 2,
        "enName": "b",
        "trName": "b",
        "parent_id": 3
    },
    {
        "id": 3,
        "enName": "c",
        "trName": "c",
        "parent_id": 3
    },
]

我用这个序列化器；

class pagesSerializer(serializers.ModelSerializer):
    class Meta:
        model = userPages
        fields = ('id', 'enName', 'trName', 'parent_id')

这是我的方法；

class pagesListView(ListAPIView):
    serializer_class = pagesSerializer

    def get_queryset(self):
        return list(itertools.chain(userPages.objects.all(), userPageAuths.objects.all()))

我得到了这样的数据；

[
    {
        "id": 1,
        "enName": "x",
        "trName": "x",
        "parent_id": null
    },
    {
        "id": 2,
        "enName": "y",
        "trName": "y",
        "parent_id": null
    },
    {
        "id": 3,
        "enName": "z",
        "trName": "z",
        "parent_id": 2
    },
    {
        "id": 1,
        "enName": "a",
        "trName": "a",
        "parent_id": null
    },
    {
        "id": 2,
        "enName": "b",
        "trName": "b",
        "parent_id": null
    },
    {
        "id": 3,
        "enName": "c",
        "trName": "c",
        "parent_id": null
    },
]

我想得到 userpages_id 作为 a,b,c 名字的 parent_id。这可能还是其他解决方案？

Answer 1

class pagesListView(ListAPIView):
    serializer_class = pagesSerializer

    def get_queryset(self):
        all =  list(itertools.chain(userPages.objects.all()))
        serializer = pagesSerializer(all, many=True)
        json_data = json.loads(json.dumps(serializer.data))
        for element in json_data:
            if 'user_page_auths' in element:
                if element['user_page_auths']:
                    for data in element['user_page_auths']:
                        data["parent_id"] = element['id']
                        json_data.append(data)
                    del element['user_page_auths']
                else:
                    del element['user_page_auths']
        return json_data

我使用上面的解析数据解决了我的问题。

使用模型字段一起获取 Django 模型中的多对多字段

Get Many to many fileds in django model with together model fields

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many-to-many

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