运行 对同一个 table 的两个查询并在同一路由上实现它们
Running two queries on the same table and implement them on the same route
我怎样才能使这个工作?
我想我应该使用 promises,但我对它们知之甚少。我读过它们,但无法创建应有的结构。
我只想 运行 对同一个 table 两个不同的查询,并在同一个 ejs 文件上使用返回值
app.get('/', (req, res) => {
db.query('SELECT COUNT(*) AS count, FORMAT(SUM(donation_amount),2) AS total FROM donations;', (err, result) => {
if (err) throw err;
let count = result[0].count; //since query column is requested as "count". we can use "count" to get back the raw value
let total = result[0].total;
res.render('home', { count: count, total: total }); // just the file name is enough. ejs engine looks up the file name in the "views" folder
});
db.query('SELECT CONCAT(first_name, ", ", last_name AS latest_donator, donation_amount AS amount FROM donations ORDER BY donation_time LIMIT 1;', (err, result) => {
if (err) throw err;
let donatorName = result[0].latest_donator;
let amount = result[0].amount;
res.render('home', {first_name: donatorName, amount: amount});
});
});
您只有在获得两个查询的结果后才能发送响应 (res.render(...)
)。因此,您可能希望像这样按顺序执行它们。
app.get('/', (req, res) => {
db.query('SELECT COUNT(*) AS count, FORMAT(SUM(donation_amount),2) AS total FROM donations;', (err, result) => {
if (err) throw err;
let count = result[0].count; //since query column is requested as "count". we can use "count" to get back the raw value
let total = result[0].total;
db.query('SELECT CONCAT(first_name, ", ", last_name AS latest_donator, donation_amount AS amount FROM donations ORDER BY donation_time LIMIT 1;', (err, result) => {
if (err) throw err;
let donatorName = result[0].latest_donator;
let amount = result[0].amount;
res.render('home', { first_name: donatorName, amount: amount, count: count, total: total });
});
});
});
但是查询彼此独立,因此您可以 运行 它们并行。
我怎样才能使这个工作?
我想我应该使用 promises,但我对它们知之甚少。我读过它们,但无法创建应有的结构。
我只想 运行 对同一个 table 两个不同的查询,并在同一个 ejs 文件上使用返回值
app.get('/', (req, res) => {
db.query('SELECT COUNT(*) AS count, FORMAT(SUM(donation_amount),2) AS total FROM donations;', (err, result) => {
if (err) throw err;
let count = result[0].count; //since query column is requested as "count". we can use "count" to get back the raw value
let total = result[0].total;
res.render('home', { count: count, total: total }); // just the file name is enough. ejs engine looks up the file name in the "views" folder
});
db.query('SELECT CONCAT(first_name, ", ", last_name AS latest_donator, donation_amount AS amount FROM donations ORDER BY donation_time LIMIT 1;', (err, result) => {
if (err) throw err;
let donatorName = result[0].latest_donator;
let amount = result[0].amount;
res.render('home', {first_name: donatorName, amount: amount});
});
});
您只有在获得两个查询的结果后才能发送响应 (res.render(...)
)。因此,您可能希望像这样按顺序执行它们。
app.get('/', (req, res) => {
db.query('SELECT COUNT(*) AS count, FORMAT(SUM(donation_amount),2) AS total FROM donations;', (err, result) => {
if (err) throw err;
let count = result[0].count; //since query column is requested as "count". we can use "count" to get back the raw value
let total = result[0].total;
db.query('SELECT CONCAT(first_name, ", ", last_name AS latest_donator, donation_amount AS amount FROM donations ORDER BY donation_time LIMIT 1;', (err, result) => {
if (err) throw err;
let donatorName = result[0].latest_donator;
let amount = result[0].amount;
res.render('home', { first_name: donatorName, amount: amount, count: count, total: total });
});
});
});
但是查询彼此独立,因此您可以 运行 它们并行。