使用 scan 方法 + regexp 将字符串分解为单词，如果单词有 `'` 字符，则删除该字符及其后的所有内容
Break string into words using scan method + regexp, if word has `'` character, drop this character and everything after it
sample_string = "let's could've they'll you're won't"
sample_string.scan(/\w+/)
上面给了我：
["let", "s", "could", "ve", "they", "ll", "you", "re", "won", "t"]
我想要的：
["let", "could", "they", "you", "won"]
一直在 https://rubular.com/ 尝试并尝试像 \w+(?<=') 这样的断言，但没有运气。
您可以使用
sample_string.scan(/(?<![\w'])\w+/)
sample_string.scan(/\b(?<!')\w+/)
见Rubular demo。模式（它们是绝对同义词）匹配
(?<![\w']) - 字符串中未紧跟单词或 ' char\b(?<!') - 没有紧跟 ' char\w+ - 一个或多个单词字符。
sample_string = "let's could've they'll you're won't"
p sample_string.scan(/(?<![\w'])\w+/)
# => ["let", "could", "they", "you", "won"]
鉴于：
> sample_string = "let's could've they'll you're won't"
您可以进行拆分和映射：
> sample_string.split.map{|w| w.split(/'/)[0]}
=> ["let", "could", "they", "you", "won"]
sample_string = "let's could've they'll you're won't"
sample_string.scan(/\w+/)
上面给了我：
["let", "s", "could", "ve", "they", "ll", "you", "re", "won", "t"]
我想要的：
["let", "could", "they", "you", "won"]
一直在 https://rubular.com/ 尝试并尝试像 \w+(?<=') 这样的断言，但没有运气。
您可以使用
sample_string.scan(/(?<![\w'])\w+/)
sample_string.scan(/\b(?<!')\w+/)
见Rubular demo。模式（它们是绝对同义词）匹配
(?<![\w'])- 字符串中未紧跟单词或'char 的位置
\b(?<!')- 没有紧跟'char 的单词边界位置
\w+- 一个或多个单词字符。
sample_string = "let's could've they'll you're won't"
p sample_string.scan(/(?<![\w'])\w+/)
# => ["let", "could", "they", "you", "won"]
鉴于：
> sample_string = "let's could've they'll you're won't"
您可以进行拆分和映射：
> sample_string.split.map{|w| w.split(/'/)[0]}
=> ["let", "could", "they", "you", "won"]