R - 遍历 2 个列表和 return 个列表

Question

我正在尝试遍历 2 个列表（实际上是 2 个数据集）并按列对它们进行统计比较，return 结果按列进行。

我正在尝试使用 lapply 来执行此操作，但我无法获得正确的语法。这是我的代码的一些示例数据：

### predat and postdat are the datasets to be compared columnwise
predat<- as.data.frame(matrix(data = rnorm(25), nrow = 25, ncol = 5))
postdat<-as.data.frame(matrix(data = rnorm(25), nrow = 25, ncol = 5))
colnames(predat)<-c("x1","x2","x3","x4","x5")
colnames(postdat)<-c("y1","y2","y3","y4","y5")
predat<-as.list(predat)
postdat<-as.list(postdat)

test_out<-function(x,y){
  
  res<-wilcox.test(x,y, paired = TRUE, alternative = "two.sided")
  return(res)
  
  
}
## I want the results of comparing predat and postdat columnwise in a list
out_all<-lapply(predat,postdat, test_out)

感谢您的帮助！

Answer 1

如果我没理解错的话，你想要这个：

output <- purrr::map2(
  .x = predat,
  .y = postdat,
  .f = test_out
)

R - 遍历 2 个列表和 return 个列表

R - iterating over 2 lists and return a list

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list