如何根据 Django 中的最新条目反向过滤

How to reverse filter based on latest entry in Django

我有一个客户 table 和客户订单 table 如下

class Customer(models.Model):
  name = models.CharField()

class CustomerOder(models.Model):
  customer = models.ForiengKey(Customer)
  item = models.CharField()
  datetime_of_purchase = models.DateField()

示例数据库条目

Table:客户

id    name
1     A
2     B
3     C

Table:客户订单

id   customer   item     datetime_of_purchase
1    A          item_3   2021-11-10 10:00:00
2    A          item_2   2021-11-11 10:00:00
3    B          item_1   2021-11-11 10:00:00
4    A          item_1   2021-11-12 10:00:00
5    B          item_2   2021-11-12 10:00:00
6    C          item_1   2021-11-13 10:00:00

假设我需要过滤最近一次购买 'items_1' 的客户,那么过滤后的样本应该只得到最近一次购买 'item_1' 的客户 'A' 和 'C'

Sample:
<QuerySet [<Customer: A>, <Customer: C>]>

您可以通过Subquery expression [Django-doc]获取最新购买的商品:

from django.db.models import <strong>OuterRef, Subquery</strong>

Customer.objects.alias(
    <strong>latest_purchase=Subquery(</strong>
        CustomerOrder.objects.filter(
            customer_id=OuterRef('pk')
        ).order_by('-datetime_of_purchase').values('item')[:1]
    <strong>)</strong>
).filter(<strong>latest_purchase='item_1'</strong>)

, one uses .annotate(…) [Django-doc] over .alias(…) [Django-doc]之前:

from django.db.models import <strong>OuterRef, Subquery</strong>

Customer.objects.annotate(
    <strong>latest_purchase=Subquery(</strong>
        CustomerOrder.objects.filter(
            customer_id=OuterRef('pk')
        ).order_by('-datetime_of_purchase').values('item')[:1]
    <strong>)</strong>
).filter(<strong>latest_purchase='item_1'</strong>)