如何根据 Django 中的最新条目反向过滤
How to reverse filter based on latest entry in Django
我有一个客户 table 和客户订单 table 如下
class Customer(models.Model):
name = models.CharField()
class CustomerOder(models.Model):
customer = models.ForiengKey(Customer)
item = models.CharField()
datetime_of_purchase = models.DateField()
示例数据库条目
Table:客户
id name
1 A
2 B
3 C
Table:客户订单
id customer item datetime_of_purchase
1 A item_3 2021-11-10 10:00:00
2 A item_2 2021-11-11 10:00:00
3 B item_1 2021-11-11 10:00:00
4 A item_1 2021-11-12 10:00:00
5 B item_2 2021-11-12 10:00:00
6 C item_1 2021-11-13 10:00:00
假设我需要过滤最近一次购买 'items_1' 的客户,那么过滤后的样本应该只得到最近一次购买 'item_1' 的客户 'A' 和 'C'
Sample:
<QuerySet [<Customer: A>, <Customer: C>]>
您可以通过Subquery
expression [Django-doc]获取最新购买的商品:
from django.db.models import <strong>OuterRef, Subquery</strong>
Customer.objects.alias(
<strong>latest_purchase=Subquery(</strong>
CustomerOrder.objects.filter(
customer_id=OuterRef('pk')
).order_by('-datetime_of_purchase').values('item')[:1]
<strong>)</strong>
).filter(<strong>latest_purchase='item_1'</strong>)
在django-3.2, one uses .annotate(…)
[Django-doc] over .alias(…)
[Django-doc]之前:
from django.db.models import <strong>OuterRef, Subquery</strong>
Customer.objects.annotate(
<strong>latest_purchase=Subquery(</strong>
CustomerOrder.objects.filter(
customer_id=OuterRef('pk')
).order_by('-datetime_of_purchase').values('item')[:1]
<strong>)</strong>
).filter(<strong>latest_purchase='item_1'</strong>)
我有一个客户 table 和客户订单 table 如下
class Customer(models.Model):
name = models.CharField()
class CustomerOder(models.Model):
customer = models.ForiengKey(Customer)
item = models.CharField()
datetime_of_purchase = models.DateField()
示例数据库条目
Table:客户
id name
1 A
2 B
3 C
Table:客户订单
id customer item datetime_of_purchase
1 A item_3 2021-11-10 10:00:00
2 A item_2 2021-11-11 10:00:00
3 B item_1 2021-11-11 10:00:00
4 A item_1 2021-11-12 10:00:00
5 B item_2 2021-11-12 10:00:00
6 C item_1 2021-11-13 10:00:00
假设我需要过滤最近一次购买 'items_1' 的客户,那么过滤后的样本应该只得到最近一次购买 'item_1' 的客户 'A' 和 'C'
Sample:
<QuerySet [<Customer: A>, <Customer: C>]>
您可以通过Subquery
expression [Django-doc]获取最新购买的商品:
from django.db.models import <strong>OuterRef, Subquery</strong>
Customer.objects.alias(
<strong>latest_purchase=Subquery(</strong>
CustomerOrder.objects.filter(
customer_id=OuterRef('pk')
).order_by('-datetime_of_purchase').values('item')[:1]
<strong>)</strong>
).filter(<strong>latest_purchase='item_1'</strong>)
在django-3.2, one uses .annotate(…)
[Django-doc] over .alias(…)
[Django-doc]之前:
from django.db.models import <strong>OuterRef, Subquery</strong>
Customer.objects.annotate(
<strong>latest_purchase=Subquery(</strong>
CustomerOrder.objects.filter(
customer_id=OuterRef('pk')
).order_by('-datetime_of_purchase').values('item')[:1]
<strong>)</strong>
).filter(<strong>latest_purchase='item_1'</strong>)