为什么当我将此函数设置为 return 时,该函数会无限重复?

Why when I make this function return its value, the function repeats itself infinitely?

这是我的代码,在该行中,我对造成此问题的 return 进行了评论。

from pynput import mouse

def on_move(m_x, m_y):
    print('Pointer moved to {0}'.format((m_x, m_y)))

def on_click(m_x, m_y, button, pressed):

    #print('{0} at {1}'.format('Pressed' if pressed else 'Released',(m_x, m_y)))

    if(pressed):
        print("Pressed")
    else:
        print("( x = "+ str(m_x) + ", y = " + str(m_y) + " )")
        return(m_x, m_y) #this is the return

    if not pressed:
        # Stop listener
        return False

def on_scroll(m_x, m_y, dm_x, dm_y):
    print('Scrolled {0} at {1}'.format(
        'down' if dy < 0 else 'up',
        (m_x, m_y)))

# Collect events until released
with mouse.Listener(on_move=on_move, on_click=on_click, on_scroll=on_scroll) as listener:
    listener.join()

# ...or, in a non-blocking fashion:
listener = mouse.Listener(on_move=on_move, on_click=on_click, on_scroll=on_scroll)
A_coord_x, A_coord_y = mouse.Listener(on_move=on_move, on_click=on_click, on_scroll=on_scroll)
#listener.start()


print (A_coord_x)
print (A_coord_y)

我唯一想要的是点击后坐标保存在变量 A_coord_xA_coord_y

on_click() 是一个事件处理程序,您不能从中获取 return 值,return False 语句只会停止侦听器。只需从处理程序中调用 set_coordinates(x,y) 函数,您应该会得到预期的结果。

也许还可以看看 documentation,这里有一个关于如何使用 mouse.listener

的示例

这是给你的答案。这将释放 listener 并为您提供 A_coord_xA_coord_y

中的坐标
from pynput.mouse import Listener

A_coord_x, A_coord_y = 0, 0


def on_click(x, y, button, pressed):
    global A_coord_x, A_coord_y
    if pressed:
        A_coord_x, A_coord_y = x, y
        print('{0} at {1}'.format(
            'Pressed' if pressed else 'Released',
            (x, y)))
        return x,y
    if not pressed:
        # Stop listener
        return False


with Listener(on_click=on_click) as listener:
    coords = listener.join()


print ('X coordinates :',A_coord_x)
print ('Y coordinates :',A_coord_y)

输出:

Pressed at (1211, 400)
X coordinates : 1211
Y coordinates : 400