SQL Sum with Group By 不接受仅一列

Question

我用一种数学表达式进行了查询，但结果不是我所期望的。

查询是：

SELECT c.nome,round((d.montante / SUM(d.montante) OVER()),2)* 100 FROM dado d 
join categoria c on d.categoria_id = c.id where cast(d.tipologia_enum as text)
 =:tipologia and extract(year from d.data) in :anos and extract(month from d.data)
 in :meses group by c.nome,d.montante

结果是：

nome	column
Alimentação e Bebidas	9
Alimentação e Bebidas	20
Alimentação e Bebidas	56
Casa e Serviços	6
Compras	9

问题是我只想按第一列分组，然后对第二列求和，但不知何故我做不到，因为它给了我这个错误：

"SQL Error [42803]: ERROR: column "d.montante" must appear in the GROUP BY clause or be used in an aggregate function"

有人可以帮我吗？

Answer 1

如果您想要按类别的百分比，因为所需的输出意味着您可以组合 SUM 聚合和 SUM window 函数

SELECT c.nome, round((SUM(d.montante) / SUM(SUM(d.montante)) OVER()), 2) * 100 
FROM dado d 
join categoria c on d.categoria_id = c.id 
where cast(d.tipologia_enum as text)
   =:tipologia and extract(year from d.data) in :anos and extract(month from d.data)
 in :meses 
group by c.nome

SQL Sum with Group By 不接受仅一列

SQL Sum with Group By not accepting only one column

sql

postgresql

group-by

sum