Groovy：将响应与 json 文件进行比较，同时忽略某些键

Question

我收到来自 REST API 约 40k 行的响应，我需要验证其中的值是否与现有本地文件中的值匹配。响应确实有一个特定的动态元素，它基于收到响应的日期和时间。

我需要将响应与本地 json 文件进行比较并确保值匹配，同时忽略通过的特定日期和时间元素。

这是 response/json 文件的片段示例：

[
   {
      "code" : "SJM",
      "valuesCount" : [
         {
            "code" : "SJM",
            "description" : "LAST_NAME FIRST_NAME-SJM (LMM/null)",
            "period" : "November 2020",
            "printedOn" : "31/01/2022 09:39:39",
            "name" : "null",
            "logo" : { },
            "standardId" : true,
            "dailyValues" : [
               {
                  "index" : "odd",
                  "day" : "01",
                  "description" : "",
                  "time" : "23:59",
                  "cms" : "",
                  "hcv" : "",
                  "nm" : "",
                  "hcp" : "",
                  "hcz" : "",
                  "synDc" : "",
                  "jiJnm" : "",
                  "c1" : "",
                  "c2" : "",
                  "proHvs" : "",
                  "dcd" : "",
                  "dcs" : "",
                  "d1" : "",
                  "d2" : "",
                  "nbdays" : ""
               },
            ]
         }
    }
  ]
]

该文件包含数百个 code 条目，每个条目都有自己的 valuesCount 映射，其中出现了 printedOn 元素，这就是我试图忽略的内容。

我一直在 Groovy 中尝试这样做，我在 groovy 文档中找到的唯一东西是 removeAll() 方法，我认为我可以删除完全 key:value 但我认为我没有正确使用它。

import groovy.json.*

def groovyUtils = new com.eviware.soapui.support.GroovyUtils(context)
def projectDir = groovyUtils.projectPath

def response = new JsonSlurper().parseText(context.expand( '${Request#Response}' ))
File jsonFile = new File(projectDir, "/Project/Resources/jsonFile.json")
def defaultValues = new JsonSlurper().parse(jsonFile)




var1 = response.removeAll{"printedOn"}

var2 = defaultValues.removeAll{"printedOn"}

   if (var1 == var2) {
    log.info "The request matches the default values."
   } else {
    throw new Exception("The request does not match the default values.");
   }

这只是 returns 两种情况的真实陈述。

谁能指出我正确的方向？非常感谢。

Answer 1

您需要遍历 lists/maps 的层次结构以更改内部映射并删除 printedOn key/value 对。

你的 json 也被 missing/extra 括号破坏了。

以下代码：

import groovy.json.*

def data1 = '''\
[
  {
    "code": "SJM",
    "valuesCount": [
      {
        "code": "SJM",
        "description": "LAST_NAME FIRST_NAME-SJM (LMM/null)",
        "period": "November 2020",
        "printedOn": "31/01/2022 09:39:39",
        "name": "null",
        "logo": {},
        "standardId": true,
        "dailyValues": [
          {
            "index": "odd",
            "day": "01",
            "description": "",
            "time": "23:59",
            "cms": "",
            "hcv": "",
            "nm": "",
            "hcp": "",
            "hcz": "",
            "synDc": "",
            "jiJnm": "",
            "c1": "",
            "c2": "",
            "proHvs": "",
            "dcd": "",
            "dcs": "",
            "d1": "",
            "d2": "",
            "nbdays": ""
          }
        ]
      }
    ]
  }
]'''


def data2 = '''\
[
  {
    "code": "SJM",
    "valuesCount": [
      {
        "code": "SJM",
        "description": "LAST_NAME FIRST_NAME-SJM (LMM/null)",
        "period": "November 2020",
        "printedOn": "25/11/2021 09:39:39",
        "name": "null",
        "logo": {},
        "standardId": true,
        "dailyValues": [
          {
            "index": "odd",
            "day": "01",
            "description": "",
            "time": "23:59",
            "cms": "",
            "hcv": "",
            "nm": "",
            "hcp": "",
            "hcz": "",
            "synDc": "",
            "jiJnm": "",
            "c1": "",
            "c2": "",
            "proHvs": "",
            "dcd": "",
            "dcs": "",
            "d1": "",
            "d2": "",
            "nbdays": ""
          }
        ]
      }
    ]
  }
]'''

def parser = new JsonSlurper()
def json1 = parser.parseText(data1)
def json2 = parser.parseText(data2)

def clean1 = removeNoise(json1)
def clean2 = removeNoise(json2)

def out1 = JsonOutput.toJson(clean1)
def out2 = JsonOutput.toJson(clean2)

assert out1 == out2

if(out1 == out2) println "the two documents are identical"
else             println "the two documents differ"

def removeNoise(json) {
  json.collect { codeMap -> 
    codeMap.valuesCount = codeMap.valuesCount.collect { valuesMap -> 
      valuesMap.remove('printedOn')
      valuesMap
    }
    codeMap
  }
}

执行时会产生如下输出：

─➤ groovy solution.groovy                                                                                
the two documents are identical

─➤

上面代码中的 json 已更正为可解析。我手动更改了字符串日期，以便 data1 和 data2 在 printedOn 属性.

上有所不同

编辑 - 看来你实际上可以这样做：

assert clean1 == clean2
// or 
if (clean1 == clean2) ...

用于比较。减少了 json 的额外序列化步骤，但也让我觉得在比较像这样的嵌套数据结构时相信 groovy 做正确的事情有点不舒服。

我可能还是会继续连载。

Groovy：将响应与 json 文件进行比较，同时忽略某些键

Groovy: Compare a response with a json file while ignoring certain keys

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