使用 jq 将 bash-array 写入 json：每个对象一个元素

Question

我正在尝试将 bash 数组中的一些值保存到现有的 json 中。我尝试了一些不同的方法，但未能解决问题。我在这里错过了什么？

input.json

{
"type": "FeatureCollection",
"name": "test",
"features": [
{ "type": "Feature", "properties": { "OBJECTID": 3213, "USE": "dem", "tile": "4045644"}},
{ "type": "Feature", "properties": { "OBJECTID": 3214, "USE": "dem", "tile": "4045646"}},
{ "type": "Feature", "properties": { "OBJECTID": 3215, "USE": "dem", "tile": "4045648"}}
]
}

Bash 中某些计算的输出 - 100% 来自 input.json。所以这个数组长度 == input.json

中“features[]”数组的长度

printf '%s\n' "${pushintojson[@]}"

4045646 NV NV NV 
4045648 NV 4045644 NV 
4045650 NV 4045646 NV

jq '.features |= map(.properties +=  {NOSW: $ARGS.positional})' --args "${pushintojson[@]}"  <<< "${input.json}"

所以这会产生这个（我为便于阅读而添加的换行符）：

{
"type":"FeatureCollection",
"name":"test",
"features": [
{"type":"Feature","properties":{"OBJECTID":3213,"USE":"dem","tile":"4045644",
"NOSW":[
"4045646 NV NV NV",
"4045648 NV 4045644 NV",
"4045650 NV 4045646 NV"
]}},

{"type":"Feature","properties":{"OBJECTID":3214,"USE":"dem","tile":"4045646",
"NOSW":[
"4045646 NV NV NV",
"4045648 NV 4045644 NV",
"4045650 NV 4045646 NV"
]}},

{"type":"Feature","properties":{"OBJECTID":3215,"USE":"dem","tile":"4045648",
"NOSW":[
"4045646 NV NV NV",
"4045648 NV 4045644 NV",
"4045650 NV 4045646 NV"
]}}
]
}

bash 数组的所有值都保存到每个元素。每个 json-object 应该只有一个值——实际上是一个数组本身。所以在伪：“pushintojson[0]”需要在“features[0]”下，pushintojson[1]”到“features[1]” pushintojson[2]”到“features[2]”等等

期望的输出

{
"type":"FeatureCollection",
"name":"test",
"features": [
{"type":"Feature","properties":{"OBJECTID":3213,"USE":"dem","tile":"4045644",
"NOSW":"4045646 NV NV NV"
}},
{"type":"Feature","properties":{"OBJECTID":3214,"USE":"dem","tile":"4045646",
"NOSW":"4045648 NV 4045644 NV"
}},
{"type":"Feature","properties":{"OBJECTID":3215,"USE":"dem","tile":"4045648",
"NOSW":"4045650 NV 4045646 NV"
}}
]
}

Answer 1

如果您只使用 map，那么对于每个元素，您最终都会再次遍历所有参数。相反，您必须将 .features 数组与 $ARGS.positional 数组对齐。

一种更接近您尝试的方法是使用 to_entries 扩展 .features 数组，使数组的元素与其键匹配，而键又可以在 [=13] 中使用=] 通过索引引用 $ARGS.positional 数组的相应项。

jq '
  .features |= (to_entries | map(
    .value * {properties: {NOSW: $ARGS.positional[.key]}}
  ))
' --args "${pushintojson[@]}" < input.json

另一种方法是使用 transpose 从两个初始数组生成一个对齐项目的数组，然后再次 map 它们的内容在一起。

jq '
  .features |= ([., $ARGS.positional] | transpose | map(
    .[0] * {properties: {NOSW: .[1]}}
  ))
' --args "${pushintojson[@]}" < input.json

两者都产生

{
  "type": "FeatureCollection",
  "name": "test",
  "features": [
    {
      "type": "Feature",
      "properties": {
        "OBJECTID": 3213,
        "USE": "dem",
        "tile": "4045644",
        "NOSW": "4045646 NV NV NV"
      }
    },
    {
      "type": "Feature",
      "properties": {
        "OBJECTID": 3214,
        "USE": "dem",
        "tile": "4045646",
        "NOSW": "4045648 NV 4045644 NV"
      }
    },
    {
      "type": "Feature",
      "properties": {
        "OBJECTID": 3215,
        "USE": "dem",
        "tile": "4045648",
        "NOSW": "4045650 NV 4045646 NV"
      }
    }
  ]
}

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