在字典列表列表中用空格替换下划线

Question

我正在尝试使用以下代码将字典列表中的每个下划线“_”替换为白色space：

d=[[{"30": "PRIORITY"}, {"2022:02:25-12:06:09": "TIMESTAMP"}, {"tester": "HOSTNAME"}, {"named": "APPNAME"}, {"3456": "PID"}, {"resolver_priming_query_complete": "ACTION"}]]
f=''
def Regler(d):
    for i in d:
        for j in i:
            for k in j.keys():
                if('_' in k):
                    k=k.replace('_', ' ')
                    print(d)
Regler(d)

我想要的输出是相同的输入，但只是用 space 替换下划线，我不确定我在代码中遗漏了什么

Answer 1

最好只写一个新版本的字典，而不是修改现有的字典

d=[[{"30": "PRIORITY"}, {"2022:02:25-12:06:09": "TIMESTAMP"}, {"tester": "HOSTNAME"}, {"named": "APPNAME"}, {"3456": "PID"}, {"resolver_priming_query_complete": "ACTION"}]]
f=''
def Regler(d):
    modified_input = []
    for i in d:
        for j in i:
            temp_dict = {}
            for k, value in j.items():
                if('_' in k):
                    k=k.replace('_', ' ')
                temp_dict[k] = value
            modified_input.append(temp_dict)
        return [modified_input]

print(Regler(d))

Answer 2

列表推导式和字典推导式旨在构建列表和字典。

我们可以为列表列表的每个子列表中的每个字典构建一个新字典（没有下划线）：

def regler(lst_of_lst):
    return [
        [
            # Build dictionary with out underscores in key
            {k.replace('_', ' '): v for k, v in d.items()}
            for d in sublist
        ]
        for sublist in lst_of_lst
    ]

用样例测试：

d = [[{"30": "PRIORITY"}, {"2022:02:25-12:06:09": "TIMESTAMP"},
      {"tester": "HOSTNAME"}, {"named": "APPNAME"}, {"3456": "PID"},
      {"resolver_priming_query_complete": "ACTION"}]]

print(regler(d))

输出：

[[{'30': 'PRIORITY'},
  {'2022:02:25-12:06:09': 'TIMESTAMP'},
  {'tester': 'HOSTNAME'},
  {'named': 'APPNAME'},
  {'3456': 'PID'},
  {'resolver priming query complete': 'ACTION'}]]

在字典列表列表中用空格替换下划线

Replace underscore with whitespace in a list of list of dictionaries

python

replace

function