在Golang中如何在没有整数的范围内生成随机长度的随机字符串
In Golang How to generate a random string of random length within range without integers
我尝试使用正则表达式从生成的字符串中删除整数,但这不会给我所需范围内的长度(许多会小于最小值)
package main
import (
"fmt"
"log"
"math/rand"
"regexp"
"time"
)
func randomString(length int) string {
rand.Seed(time.Now().UnixNano())
b := make([]byte, length)
rand.Read(b)
return fmt.Sprintf("%x", b)[:length]
}
func randomLength(minL, maxL int) int {
rand.Seed(time.Now().UnixNano())
return rand.Intn(maxL-minL) + minL
}
func main() {
reg, err := regexp.Compile("[^a-zA-Z]+")
if err != nil {
log.Fatal(err)
}
for i := 0; i < 10; i++ {
processedString := reg.ReplaceAllString(randomString(randomLength(8, 16)), "")
println(processedString)
}
}
编辑:
当我搜索问题时,我错过了该问题中的详细@icza answer。
var seededRand = rand.New(rand.NewSource(time.Now().UnixNano()))
func StringWithCharset(length int, charset string) string {
b := make([]byte, length)
for i := range b {
b[i] = charset[seededRand.Intn(len(charset)-1)]
}
return string(b)
}
func main() {
rangeStart := 0
rangeEnd := 10
offset := rangeEnd - rangeStart
randLength := seededRand.Intn(offset) + rangeStart
charSet := "aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZ"
randString := StringWithCharset(randLength, charSet)
}
您只需定义您正在使用的字母表。类似于以下内容(您可以 fiddle with it here in the Go Playground)。
package main
import (
"fmt"
"math/rand"
"strings"
"time"
)
func main() {
rand.Seed(time.Now().UnixNano())
var alphabet []rune = []rune("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz")
rs := randomString(20, alphabet)
fmt.Printf("This is pretty random: %s\n", rs)
}
func randomString(n int, alphabet []rune) string {
alphabetSize := len(alphabet)
var sb strings.Builder
for i := 0; i < n; i++ {
ch := alphabet[rand.Intn(alphabetSize)]
sb.WriteRune(ch)
}
s := sb.String()
return s
}
我尝试使用正则表达式从生成的字符串中删除整数,但这不会给我所需范围内的长度(许多会小于最小值)
package main
import (
"fmt"
"log"
"math/rand"
"regexp"
"time"
)
func randomString(length int) string {
rand.Seed(time.Now().UnixNano())
b := make([]byte, length)
rand.Read(b)
return fmt.Sprintf("%x", b)[:length]
}
func randomLength(minL, maxL int) int {
rand.Seed(time.Now().UnixNano())
return rand.Intn(maxL-minL) + minL
}
func main() {
reg, err := regexp.Compile("[^a-zA-Z]+")
if err != nil {
log.Fatal(err)
}
for i := 0; i < 10; i++ {
processedString := reg.ReplaceAllString(randomString(randomLength(8, 16)), "")
println(processedString)
}
}
编辑: 当我搜索问题时,我错过了该问题中的详细@icza answer。
var seededRand = rand.New(rand.NewSource(time.Now().UnixNano()))
func StringWithCharset(length int, charset string) string {
b := make([]byte, length)
for i := range b {
b[i] = charset[seededRand.Intn(len(charset)-1)]
}
return string(b)
}
func main() {
rangeStart := 0
rangeEnd := 10
offset := rangeEnd - rangeStart
randLength := seededRand.Intn(offset) + rangeStart
charSet := "aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZ"
randString := StringWithCharset(randLength, charSet)
}
您只需定义您正在使用的字母表。类似于以下内容(您可以 fiddle with it here in the Go Playground)。
package main
import (
"fmt"
"math/rand"
"strings"
"time"
)
func main() {
rand.Seed(time.Now().UnixNano())
var alphabet []rune = []rune("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz")
rs := randomString(20, alphabet)
fmt.Printf("This is pretty random: %s\n", rs)
}
func randomString(n int, alphabet []rune) string {
alphabetSize := len(alphabet)
var sb strings.Builder
for i := 0; i < n; i++ {
ch := alphabet[rand.Intn(alphabetSize)]
sb.WriteRune(ch)
}
s := sb.String()
return s
}