一次检查两种不同类型代理的条件

Question

我有蚊子和人类两种特工。他们都有不同的状态，如易感和感染。我想检查我的代理的状态并执行操作我想检查蚊子是否被感染并且人类易感然后感染人类，反之亦然。请帮助代码

to go
  ask human
  [
    set heading  random 360
    forward random 2
      
      ]
  **if any? human-here infected? true and any? mosquito-here infected? false
ask mosquito [ set infected? true
    set color red]
  tick** 
end

Answer 1

您首先需要决定要让哪些特工采取必要的行动来感染或被感染。为此，我建议使用“with”原语，它允许您创建代理集的子集，以便检查它们是否可以被感染。 humans with [susceptible? = true and infected? = false]

之后你可以要求这个小组检查自己被感染的必要条件。 if any? mosquitos-here with [infected? = true] [set infected? true]

我建议对人类和蚊子分别进行此操作，因为两者的条件可能不同。合并后，您的代码可能如下所示：

to go
  ask humans
  [
    set heading  random 360
    forward random 2
      ]
  
  ask mosquitos
  [
    set heading  random 360
    forward random 2
      ]  
  
  ask humans with [susceptible? = true and infected? = false] [
    if any? mosquitos-here with [infected? = true] [set infected? true set color red]
]
  
  ask mosquitos with [susceptible? = true and infected? = false] [
    if any? humans-here with [infected? = true] [set infected? true set color red]
]
  
  tick
end

如果感染以对称方式发生，你也可以使用类似下面的方法，但我不建议这样做，因为我假设你想要区分人类和蚊子

  ask turtles with [susceptible? = true and infected? = false] [
    let my-breed breed
    if any? turtles-here with [infected? = true and breed != my-breed] [set infected? true set color red]
]

一次检查两种不同类型代理的条件

checking condition for two different breed of agents at once

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