TypeError: reverse() takes exactly 2 arguments (1 given)

TypeError: reverse() takes exactly 2 arguments (1 given)

由于某些奇怪的原因,即使我的 url 没有参数,反向函数也不起作用。

Url.py:

from django.urls import path

from . import views

urlpatterns = [
    path("api/v2/app/nextdialog", views.NextDialog.as_view(), name="app-next-dialog"),
]

views.py:

class StartAssessment(generics.GenericAPIView):
    
    def post(self, request, *args, **kwargs):
        data = request.data
        request = build_rp_request(data)
        response = post_to_app_start_assessment(request)
        path = get_path(response)
        step = get_step(response)
        data["path"] = path
        data["step"] = step
        request = build_rp_request(data)
        app_response = post_to_app(request, path)
        message = format_message(app_response)
        return Response(message, status=status.HTTP_200_OK)

functions.py:

def get_endpoint(payload):
    head = {
        "Content-Type": "application/json",
    }
    url = reverse("app-next-dialog")
    response = requests.post(url, data=json.dumps(payload), headers=head)
    return response

当我 运行 这样做时,出现以下错误。

url = reverse("app-next-dialog")
TypeError: reverse() takes exactly 2 arguments (1 given)

请问有没有人知道这里出了什么问题。我认为我不需要添加任何其他论点。谢谢

您使用的是 Django reverse 还是 DRF reverse

Django 反向 return 当 DRF 反向可以 return 绝对 URI 时,它是一个相对 URI。

Django reverse 接受 1 个参数,所以这应该可以工作

url = reverse("app-next-dialog")

但是 DRF reverse 接受两个参数,例如:

url = reverse("app-next-dialog", request=request)

检查您的导入