如何比较 SQL 中的两行 JSON 值？

Question

我有一个计费数据存储在 table 中，就像 SQL 中这样。我想比较 BillContent（Json 具有未知属性的值）。我的目标是将当前版本的 BillContent 与以前版本进行比较，以查看不同部门进行了哪些更改。因此，我希望看到更改后的值。在 SQL 中完成这项工作的最简单方法是什么？

	ID	BillID	VersionNo	BillContent
1	150	9	1	{"ID":9,"Description":"testing Bill","Active":true,"AddressID":14,"DepartmentID":9,"LogbillingInfo":true,"ForwardBill":true,"VIP":false,"BillingBranchSectors":[{"SectorID":9,"InspectorID":0,"BillingMovingSteps":[]}],"BillingVersions":[]}
2	151	9	2	{"ID":9,"Description":"testing Bill","Active":true,"AddressID":14,"DepartmentID":9,"LogbillingInfo":true,"ForwardBill":true,"VIP":false,"BillingBranchSectors":[{"SectorID":9,"InspectorID":0,"BillingMovingSteps":[]}],"BillingVersions":[]}
3	152	9	3	{"ID":9,"Description":"testing Billagain","Active":true,"AddressID":14,"DepartmentID":9,"LogbillingInfo":true,"CancellingBillingInfo":false,"ForwardBill":true,"VIP":false,"BillingBranchSectors":[{"SectorID":9,"InspectorID":0,"BillingMovingSteps":[]}],"BillingMetaData[]":,"BillingVersions":[]}

首先我用这个语句得到上面的table：

select bvt.*
from BillVersionTable bvt
where BillID = 9
enter code here

所需解决方案的输出可能只是得到两个 Json 之间的差异，例如下面的 table：

可能的输出 1： 此输出 returns json 仅具有在比较版本与原始版本时不同或更改的属性

	Difference
1	{"Description":"testing","LogbillingInfo":false,"ForwardBill":false,"VIP":false}

可能的输出 2： 此输出 returns 一个 VersionNo 和 json 的每个属性作为所有版本的列给定的过程。注意：某些属性具有嵌套数组。

	VersionNo	ID	Description	Active	AddressID	DepartmentID	LogbillingInfo	ForwardBill	VIP	BillingBranchSectors	BillingMetaData	BillingVersions
1	1	9	testing Bill	true	14	9	true	true	false	[{"SectorID":9,"InspectorID":0,"BillingMovingSteps":[]}]	NULL	NULL
2	2	9	testing Bill	true	14	9	true	true	false	[{"SectorID":9,"InspectorID":0,"BillingMovingSteps":[]}]	NULL	NULL
3	3	9	testing Billagain	true	14	9	true	false	true	[{"SectorID":9,"InspectorID":2,"BillingMovingSteps":[]}]	["metaDatasteps": true, DescriptiveDetail:[]]	NULL

可能的解决方案： 比较这些帐单版本的最简单方法是使用 SQL 内置 JSON_VALUE，正如下面 YuTing 所建议的。这将 return 来自版本 table 的 BillContent (JSON) 的每个属性作为给定账单 ID 的所有版本的列。对于已知 JSON 对象的属性的情况，这是一个很好的解决方案。但是，JSON_VALUE 不适用于数组，因为我们在包含数组的 JOSN 中有一些属性，例如 'BillingVersions'。这就是 JSON_QUERY 的来源。 bill id 9的这种做法的例子如下：

    select bv.VersionNo,
JSON_VALUE(BillContent, '$.ID') AS ID,
JSON_VALUE(BillContent, '$.Description') AS Description,
JSON_VALUE(BillContent, '$.Active') AS Active,
JSON_VALUE(BillContent, '$.AddressID') AS AddressID,
JSON_VALUE(BillContent, '$.DepartmentID') AS DepartmentID,
JSON_VALUE(BillContent, '$.LogbillingInfo') AS LogbillingInfo,
JSON_VALUE(BillContent, '$.CancellingBillingInfo') AS CancellingBillingInfo,
JSON_VALUE(BillContent, '$.ForwardBill') AS ForwardBill,
JSON_VALUE(BillContent, '$.VIP') AS VIP,
JSON_QUERY(BillContent, '$.BillingBranchSectors') AS BillingBranchSectors,
JSON_QUERY(BillContent, '$.BillingVersions') AS BillingVersions,
JSON_QUERY(BillContent, '$.BillingMetaData') AS BillingMetaData
from BillVersionTable bv
where BillID = 9

Answer 1

使用json_value，查看微软的文档。

CREATE TABLE data
(
    ID int NOT NULL,
    BillID int NOT NULL,
    VersionNo int NOT NULL,
    BillContent nvarchar(1000) NOT NULL,
);

insert into data values
 (150, 9, 1, '{"ID":9,"Description":"testing Bill","Active":true,"AddressID":14,"DepartmentID":9,"LogbillingInfo":true,"ForwardBill":true,"VIP":false,"BillingBranchSectors":[{"SectorID":9,"InspectorID":0,"BillingMovingSteps":[]}],"BillingVersions":[]}')
,(151, 9, 2, '{"ID":9,"Description":"testing Bill","Active":true,"AddressID":14,"DepartmentID":9,"LogbillingInfo":true,"ForwardBill":true,"VIP":false,"BillingBranchSectors":[{"SectorID":9,"InspectorID":0,"BillingMovingSteps":[]}],"BillingVersions":[]}')
,(152, 9, 3, '{"ID":9,"Description":"testing Billagain","Active":true,"AddressID":14,"DepartmentID":9,"LogbillingInfo":true,"CancellingBillingInfo":false,"ForwardBill":true,"VIP":false,"BillingBranchSectors":[{"SectorID":9,"InspectorID":0,"BillingMovingSteps":[]}],"BillingMetaData":[],"BillingVersions":[]}')

select 
JSON_VALUE(BillContent, '$.ID') AS ID,
JSON_VALUE(BillContent, '$.Description') AS Description,
JSON_VALUE(BillContent, '$.Active') AS Active,
JSON_VALUE(BillContent, '$.AddressID') AS AddressID,
JSON_VALUE(BillContent, '$.DepartmentID') AS DepartmentID,
JSON_VALUE(BillContent, '$.LogbillingInfo') AS LogbillingInfo,
JSON_VALUE(BillContent, '$.CancellingBillingInfo') AS CancellingBillingInfo,
JSON_VALUE(BillContent, '$.ForwardBill') AS ForwardBill,
JSON_VALUE(BillContent, '$.VIP') AS VIP,
JSON_VALUE(BillContent, '$.BillingBranchSectors') AS BillingBranchSectors,
JSON_VALUE(BillContent, '$.BillingVersions') AS BillingVersions,
JSON_VALUE(BillContent, '$.BillingMetaData') AS BillingMetaData
from data
where BillID = 9

dbfiddle

如何比较 SQL 中的两行 JSON 值？

How to compare two rows of JSON values in SQL?

sql

sql-server