for循环填充django模板table

Question

我正在尝试在 Django 模板中制作 table。我正在像这样在 views.py 中发送一个字典作为我的数据：

from posixpath import split
from unittest import result
from django.shortcuts import render
import requests

from .utils import most_frequent, get_json_values, get_max_dict

def launches(request):
"""main request. Retrieve the year that had most launches"""
response_launches = 
requests.get('https://api.spacexdata.com/v3/launches? 
filter=launch_year')
launches = response_launches.json()
launch_years = get_json_values('launch_year',launches)
result_launches = most_frequent(launch_years)

"""retrieve the launch site most used for launches """
response_sites = 
requests.get('https://api.spacexdata.com/v3/launches? 
filter=launch_site')
sites = response_sites.json()
launch_sites = get_json_values("launch_site", sites)
result_sites = get_max_dict(launch_sites,'site_id')

"""retrieve the number of launches between 2019 and 2021"""
response_2019_2021 = 
requests.get('https://api.spacexdata.com/v3/launches? 
start=2019&end=2021')
launches_2019_2021 = response_2019_2021.json()
result_2019_2021 = len(launches_2019_2021)

data = {
    "year_most_launches": result_launches,
    "launch_sites":result_sites,
    "launches_2019_2021":result_2019_2021
    }
print(result_launches,result_sites,result_2019_2021)
return render(request,"main/launches.html", {"data":data})

我的utils.py:

from collections import Counter
from typing import Dict, List

def most_frequent(List) -> int:
"""return the most frequent element inside a list."""
occurence_count = Counter(List)
return occurence_count.most_common(1)[0][0]

def get_json_values(key,input_data) -> List:
"""return the values of dicts inside a list."""
return [sub_val[key] for sub_val in input_data if key in sub_val]

def max_dict_value(List,key) -> List:
"""return the key that is linked to the most frequent value."""
counts = dict()
for dictionary in List:
    counts[dictionary[key]] = counts.get(dictionary[key],0) + 1
max_keys = [key for key, value in counts.items() if value == 
max(counts.values())]
return max_keys

def get_max_dict(List,key) -> List:
"""return the dictionary that maps to the max_dict_value."""
for dictionary in List:
    if dictionary[key] == max_dict_value(List,key)[0]:
        return dictionary

我的 table 在 HTML 代码中：

            <table class="table">
            <thead>
                <tr>
                    <th>Year with most launches</th>
                    <th>Launch site with most launches</th>
                    <th>Number of launches between 2019 and 2021</th>
                </tr>
            </thead>
            <tbody>
                {% for element in data.values %}
                <tr>
                    <td>{{ element }}</td>
                </tr> 
                {% endfor %} 
            </tbody>
        </table>

我的问题是数据值只出现在第一列，创建 3 行而不是只出现在第一行。

我该如何解决？这是我 html?

内部的问题

Answer 1

您的 HTML table 正在为每个元素创建一个新行 (<tr>)，您想要的是为每个元素创建一个新单元格 (<td>)每个元素，像这样：

<table class="table">
  <thead>
      <tr>
          <th>Year with most launches</th>
          <th>Launch site with most launches</th>
          <th>Number of launches between 2019 and 2021</th>
      </tr>
  </thead>
  <tbody>

      <tr>
        {% for element in data.values %}
          <td>{{ element }}</td>
        {% endfor %}
      </tr>

  </tbody>
</table>

当然，这只会产生一行，这可能是您想要的，但是如果您想要多行，则需要两个循环，一个外部循环用于每个 <tr>，一个内部循环用于每个 <td>.

for循环填充django模板table

for loop to populate a django template table

html

python

django

django-templates