剪刀石头布 Javascript（奥丁计划）

Question

大家好，这是我的第一个问题，如果它不符合所有规则，我们深表歉意。我正在尝试从 javascript 中的 Odin 项目制作剪刀石头布游戏，结果输出有问题，因为它没有显示应有的内容。如果计算机为 e 播放摇滚乐。我玩摇滚我应该得到平局但我总是随机得到一些东西。当前代码使用 prompt() 用于用户输入，但我尝试放置一个固定字符串，如“paper”，结果是一样的，我还认为这是因为我没有正确放置 toLowerCase()，所以我将其完全删除，它是还是一样，非常感谢您的帮助！

function computerPlay() {
  let rps = ["rock", "paper", "scissors"];
  let random = rps[Math.floor(Math.random() * rps.length)];
  return random;
}

console.log(computerPlay());

function playRound(playerSelection, computerSelection) {
  if (playerSelection === computerSelection) {
    return ("It's a draw!");
  } else if ((playerSelection === "rock") && (computerSelection === "scissors")) {
    return ("You win! Rock beats scissors");
  } else if (playerSelection === "rock" && computerSelection === "paper") {
    return ("You lose! Paper beats rock");
  } else if (playerSelection === "paper" && computerSelection === "rock") {
    return ("You win! Paper beats rock");
  } else if (playerSelection === "paper" && computerSelection === "scissors") {
    return ("You lose! Scissors beat paper");
  } else if (playerSelection === "scissors" && computerSelection === "paper") {
    return ("You win! Scissors beat paper");
  } else if (playerSelection === "scissors" && computerSelection === "rock") {
    return ("You lose!Rock beats scissors");
  }

}

let computerSelection = computerPlay();
let playerSelection = prompt("Choose your weapon");
console.log(playRound(playerSelection, computerSelection));

Answer 1

您首先 console.log 函数 computerPlay() 并且 returns 某个值。之后你开始玩回合并再次调用函数 computerPlay()，这会用不同于你第一次计算的另一个值计算回合 console.log。

试试下面的代码

function computerPlay() {
  let rps = ["rock", "paper", "scissors"];
  let random = rps[Math.floor(Math.random() * rps.length)];
  return random;
}


function playRound(playerSelection, computerSelection) {
  if (playerSelection === computerSelection) {
    return ("It's a draw!");
  } else if ((playerSelection === "rock") && (computerSelection === "scissors")) {
    return ("You win! Rock beats scissors");
  } else if (playerSelection === "rock" && computerSelection === "paper") {
    return ("You lose! Paper beats rock");
  } else if (playerSelection === "paper" && computerSelection === "rock") {
    return ("You win! Paper beats rock");
  } else if (playerSelection === "paper" && computerSelection === "scissors") {
    return ("You lose! Scissors beat paper");
  } else if (playerSelection === "scissors" && computerSelection === "paper") {
    return ("You win! Scissors beat paper");
  } else if (playerSelection === "scissors" && computerSelection === "rock") {
    return ("You lose!Rock beats scissors");
  }

}

let computerSelection = computerPlay();
let playerSelection = prompt("Choose your weapon");
console.log(computerSelection)
console.log(playRound(playerSelection, computerSelection));

Answer 2

你可以这样简化你的条件

const choices = ["Rock", "Paper", "Scissors"]
const computerPlay = () => choices[Math.floor(Math.random() * choices.length)]


function playRound(playerSelection, computerSelection) {
  const difference = (choices.length + choices.indexOf(playerSelection) - choices.indexOf(computerSelection) )% choices.length
  switch(difference){
   case 0:
       return "It's a draw!"
    case 2:
       return `You lose! ${computerSelection} beats ${playerSelection}`
    default:
       return `You win! ${playerSelection} beats ${computerSelection}`
  }
 
}

let computerSelection = computerPlay();
let playerSelection
while(!choices.includes(playerSelection)){
  const selected = prompt("Choose your weapon").trim().toLowerCase();
  
  playerSelection = selected[0].toUpperCase()+selected.slice(1)
 
}
console.log(playRound(playerSelection, computerSelection));

剪刀石头布 Javascript（奥丁计划）

Rock Paper Scissors Javascript (The Odin Project)

javascript

if-statement