使用 echo 从文件中 awk 并输出到文件

Question

A.txt 包含：

/*333*/
asdfasdfadfg
sadfasdfasgadas
@@@
/*555*/
hfawehfihohawe
aweihfiwahif
aiwehfwwh
@@@
/*777*/
jawejfiawjia
ajwiejfjeiie
eiuehhawefjj
@@@

B.txt 包含：

555
777

我想为在 B.txt 中找到的每个字符串创建循环，然后输出 '/*'[字符串] 直到第一个 '@@@' 遇到每个自己的文件之前（字符串名称也用作文件名）。所以根据上面的例子，结果应该是：

555.txt，其中包含：

/*555*/
hfawehfihohawe
aweihfiwahif
aiwehfwwh

和777.txt，其中包含：

/*777*/
jawejfiawjia
ajwiejfjeiie
eiuehhawefjj

我试过这个脚本，但它什么也没输出：

for i in `cat B.txt`; do echo $i | awk '/{print "/*"}/{flag=1} /@@@/{flag=0} flag' A.txt > $i.txt; done

提前致谢

Answer 1

对您的代码进行一些改动，即可使用所提供的示例数据获得所需的结果：

while read -r f
do
    awk -v var="/[*]$f[*]/" '[=10=] ~ var {flag=1} /@@@/{flag=0} flag' A.txt > "$f".txt
done < B.txt

cat 555.txt
/*555*/
hfawehfihohawe
aweihfiwahif
aiwehfwwh

cat 777.txt
jawejfiawjia
ajwiejfjeiie
eiuehhawefjj

这是否解决了您的问题？

Answer 2

使用您显示的示例，请尝试以下 awk 代码。在 GNU awk 中编写和测试应该在任何 awk.

中工作

awk '
FNR==NR{
  if([=10=]~/^\/\*/){
    line=[=10=]
    gsub(/^\/\*|\*\/$/,"",line)
    arr[++count]=[=10=]
    arr1[line]=count
    next
  }
  arr[count]=(arr[count]?arr[count] ORS:"") [=10=]
  next
}
([=10=] in arr1){
  outputFile=[=10=]".txt"
  print arr[arr1[[=10=]]] >> (outputFile)
  close(outputFile)
}
' file1 file2

说明：为以上代码添加详细说明。

awk '                                   ##Starting awk program from here.
FNR==NR{                                ##Checking condition FNR==NR which will be TRUE when file1 is being read.
  if([=11=]~/^\/\*/){                       ##Checking condition if current line starts with /* then do following.
    line=[=11=]                             ##Setting [=11=] to line variable here.
    gsub(/^\/\*|\*\/$/,"",line)         ##using gsub to globally substitute starting /* and ending */ with NULL in line here.
    arr[++count]=[=11=]                     ##Creating arr with index of ++count and value is [=11=].
    arr1[line]=count                    ##Creating arr1 with index of line and value of count.
    next                                ##next will skip all further statements from here.
  }
  arr[count]=(arr[count]?arr[count] ORS:"") [=11=]  ##Creating arr with index of count and keep appending values of same count values with current line value.
  next                                  ##next will skip all further statements from here.
}
([=11=] in arr1){                           ##checking if current line is present in arr1 then do following.
  outputFile=[=11=]".txt"                   ##Creating outputFile with current line .txt value here.
  print arr[arr1[[=11=]]] >> (outputFile)   ##Printing arr value with index of arr1[[=11=]] to outputFile.
  close(outputFile)                     ##Closing outputFile in backend to avoid too many opened files error.
}
' file1 file2                           ##Mentioning Input_file names here.

Answer 3

这是另一个 awk 解决方案：

awk '
FNR == NR {
   map["/*" [=10=] "*/"] = [=10=]
   next
}
[=10=] in map {
   fn = map[[=10=]] ".txt"
}
/^@@@$/ {
   close(fn)
   fn = ""
}
fn {print > fn}' B.txt A.txt

使用 echo 从文件中 awk 并输出到文件

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