php 中带有 switch 语句的复选框

Question

为什么当我选中两个复选框时取消它 return 2？当两个复选框都打开时，我如何 return 不同的响应？

html:

<form action="form3.php" method="POST">
 <fieldset>
  <legend> select your team </legend>
  <input type="checkbox" name="punto3" value="1"> 1 </input>
  <input type="checkbox" name="punto3" value="2"> 2 </input>
  <p><input type="submit"></p>       
 </fieldset>
</form>

php:

<?php
if (isset($_REQUEST['punto3']))
{
    $punto3 = $_REQUEST['punto3'];

    $conn = new mysqli("localhost", "root", "", "progetto2");
    if ($conn == false)
    {
    die("fail: " . $conn->connect_error);
    }

    switch ($punto3)
    {
    case '1': // 1 checkbox
    break;
    case '2': // 2 checkbox
    break;
    default: // if 1 and 2 is both checked
    }
} else {
    echo "Please, do at least one selection";
}
?>

有什么建议吗？

Answer 1

为每个复选框使用单独的名称属性值，并使用 if 条件而不是开关（或者如果您只需要一个值，则使用单选按钮）示例：

HTML:

<form action="form3.php" method="POST">
 <fieldset>
  <legend> select your team </legend>
  <input type="checkbox" name="punto3_1" value="1"> 1 </input>
  <input type="checkbox" name="punto3_2" value="2"> 2 </input>
  <p><input type="submit"></p>       
 </fieldset>
</form>

PHP:

<?php
if (
      (isset($_REQUEST['punto3_1']) && $_REQUEST['punto3_1'] != "")
      || (isset($_REQUEST['punto3_2']) && $_REQUEST['punto3_2'] != "")

)
{
    $punto3_1 = $_REQUEST['punto3_1'];
    $punto3_2 = $_REQUEST['punto3_2'];

    $conn = new mysqli("localhost", "root", "", "progetto2");
    if ($conn == false)
    {
    die("fail: " . $conn->connect_error);
    }

    if(isset($_REQUEST['punto3_1']) && $_REQUEST['punto3_1'] != ""){
        //your logic for punto3_1 will goes here....
    } elseif(isset($_REQUEST['punto3_2']) && $_REQUEST['punto3_2'] != ""){
        //your logic for punto3_2 will goes here....
    } else {
       //your logic for punto3_1 and punto3_2 will goes here....
    }
} else {
    echo "Please, do at least one selection";
}
?>

php 中带有 switch 语句的复选框

checkbox in php with switch statement

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