在 appDevDebugProjectContainer.php 中找不到 Symfony 2 错误 class

Question

我想添加具有安全上下文的表单服务，如下所示：

namespace Infogold\AccountBundle\Form;

use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolverInterface;
use Symfony\Component\Security\Core\SecurityContext;
use Doctrine\ORM\EntityRepository;

class KonsultantType extends AbstractType {

     protected $user;

    public function __construct(SecurityContext $user) {


        $this->user = $user;
    }
 public function buildForm(FormBuilderInterface $builder, array $options) {
    -
    -
    -
    -
    -
    -
  public function getName() {
        return 'konsultanci_form';
    }

在服务中：

parameters:
#    infogold_account.example.class: Infogold\AccountBundle\Example

services:

   form.type.konsultanci_form:
       class:  Infogold\AccountBundle\Form\KonsulantType
       arguments: ['@security.context'] 
       tags:
            - { name: form.type, alias: konsultanci_form }

我得到这个错误：

FatalErrorException: 错误: Class 'Infogold\AccountBundle\Form\KonsulantType' 未在 D:\xampp\htdocs\symfony4\app\cache\dev\appDevDebugProjectContainer.php 行 718

中找到

718行是：

protected function getForm_Type_KonsultanciFormService()
    {
        return $this->services['form.type.konsultanci_form'] = new \Infogold\AccountBundle\Form\KonsulantType($this->get('security.context'));
    }

我哪里弄错了？

Answer 1

正如我所说，class 名称是错误的。它是 KonsultantType 而不是 KonsulantType

尝试：

parameters:
#    infogold_account.example.class: Infogold\AccountBundle\Example

services:

   form.type.konsultanci_form:
       class:  Infogold\AccountBundle\Form\KonsultantType
       arguments: ['@security.context'] 
       tags:
            - { name: form.type, alias: konsultanci_form }

在 appDevDebugProjectContainer.php 中找不到 Symfony 2 错误 class

Symfony 2 error class not found in appDevDebugProjectContainer.php

php

symfony