Ruby 将 DD/MM/YYYY 字符串转换为 YYYY,MM,DD

Question

我正在收集用户输入 "DD/MM/YYYY"

目的是将 mktime 作为 csv YYYY,MM,DD 传递。

puts "Please enter dob in dd/mm/yyyy format;"
inp = gets.chomp
inp = inp.gsub(" ","")
while inp.length != 10
  puts "Please use dd/mm/yyyy format"
  inp = gets.chomp
end
bday = inp.gsub("/",",")

ctime = Time.new
btime = Time.mktime(bday)
lsecs = ctime - btime
ysecs = Time.mktime(2001) - Time.mktime(2000)
rsecs = 1000000000 - lsecs
ryears = rsecs / ysecs
puts "You are currently #{lsecs} seconds old"
puts "You have #{ryears} years until you are a billion seconds old!!"

如您所见，剩下的唯一任务就是反转用户输入，但很难找到紧凑的解决方案。如果您有办法，请随时帮助缩短此代码。

解决方法：（秒数和四舍五入的年份 down/delimited）

def reformat_date(str)
    str.split("/").reverse.join(",")
end

puts "Please enter dob in dd/mm/yyyy format;"
inp = gets.chomp
inp = inp.gsub(" ","")
while inp.length != 10
  puts "Please use dd/mm/yyyy format"
  inp = gets.chomp
  inp = inp.gsub(" ","")
end

ctime = Time.new
btime = Time.mktime(reformat_date(inp))
lsecs = ctime - btime
**lsecdel = lsecs.round(0).to_s.reverse.gsub(/...(?=.)/,'\&,').reverse**
ysecs = Time.mktime(2001) - Time.mktime(2000)
rsecs = 1000000000 - lsecs
ryears = rsecs / ysecs
puts "You are currently #{lsecdel} seconds old"
puts "You have #{ryears.round(2)} years until you are a billion seconds old!!"

Answer 1

怎么样？

def reformat_date(str)
  str.split('/').reverse.join(',')
end

Answer 2

require 'date'
now = Date.today

years_BACK_From_Now = (now - 365)

p years_BACK_From_Now.strftime("%m-%d-%Y").to_s

p years_BACK_From_Now.split('-').reverse.join('/')

Answer 3

您可以获得任何所需格式的输入，并使用下面的格式将其转换为 yyyy,mm,dd 格式

Date.parse("10/12/1995").strftime('%Y,%m,%d')

输出：1995,12,10

Ruby 将 DD/MM/YYYY 字符串转换为 YYYY,MM,DD

Ruby convert DD/MM/YYYY string to YYYY,MM,DD

time

date

mktime