Sum 正在返回一些模糊的值。我想要做的就是获取可变数组中的元素总和

Question

& 是的，我做了 google "How to get sum of array elements" 但我想知道这里出了什么问题？如果我使用断点并在执行此行后看到 "sum = sum + (int) A[i];" 总和有一些模糊的值。

#import <Foundation/Foundation.h>

@interface MyClass : NSObject
@end
@implementation MyClass
@end

int solution(NSMutableArray *A) 
{
  int sum = 0;
  for (int i = 0; i <A.count; i ++)
  {
    NSLog(@"A.count: %ld", A.count);
    sum = sum + (int) A[i];   //A[i] has to return a value right?**strong text** 
  }
   NSLog(@"The final sum is: %d", sum);
   return sum;
}

int main(int argc, const char * argv[]) 
{
@autoreleasepool 
{
    NSMutableArray *A = [NSMutableArray arrayWithObjects: @"3",@"1",@"2",@"4",@"3", nil];
    solution(A);        
}
return 1;
}

Answer 1

您正在添加字符串值而不是整数值。只需替换

sum = sum + (int) A[i];

与以下

sum = sum +  [A[i] integerValue];

Answer 2

数组中的元素是 NSString 个对象。您应该使用 NSNumber 个对象：

NSMutableArray *A = [@[@3,@1,@2,@4,@3] mutableCopy];

此外，您不能只将它们转换为整数。要从 NSNumber 获得 int，您需要调用 call [A[i] intValue]。否则，您将对 pointer 值求和。

 sum = sum + [A[i] intValue];

Sum 正在返回一些模糊的值。我想要做的就是获取可变数组中的元素总和

Sum is returning some vague values. All I want to do is get Sum of Elements in my Mutable Array

arrays

objective-c

literals

nsmutablearray