Laravel 5.1 试图获取属性的非对象 eloquent 关系，处理错误

Question

OrganizationsController.php

public function user_index()
{   
    if(!is_null(Organization::find(Auth::user()->player->organization))) 
    $organization = Organization::find(Auth::user()->player->organization->id);
    else $organization=null;

    return view('organizations.user_index', [ 'organization' => $organization ]);
}

为了在 "player" 没有 "organization" 时避免 "Trying to get property of non-object"，我使用了这段代码。但它似乎不太好。有没有更好的方法来获得这个？也许我错了，但是使用这种方法有一个无用的查询，对吗？

Table 玩家: id, name

Table 组织：id，名称，player_id

Answer 1

是的，对于此检查，您可能会执行一个不必要的 SQL 查询。如果你这样做，你可以摆脱这个：

if(Organization::find(Auth::user()->player->organization_id)

而不是

if(!is_null(Organization::find(Auth::user()->player->organization)))

通过这种方式，您可以在尝试获取 organization[之前检查存储在 player 中的 organization_id =21=] 来自数据库。

Answer 2

假设 user 有一个 player，并且 player 有一个 organization，并且这些关系设置正确，则不需要 Organization::find()全部。 organization 属性已经是加载的 Organization 对象，因此无需重新查找。

public function user_index() {
    // default to null
    $organization = null;

    // make sure there is an authenticated user and it has a player
    if (Auth::user() && Auth::user()->player) {
        // if the player has an organization, this will be the Organzation object
        // if the player does not have an organization, this will be null
        $organization = Auth::user()->player->organization;
    }

    return view('organizations.user_index', [ 'organization' => $organization ]);
}

Laravel 5.1 试图获取属性的非对象 eloquent 关系，处理错误

Laravel 5.1 trying to get property of non object eloquent relationship, handle error

php

laravel

eloquent

laravel-5

laravel-5.1

Laravel 5.1 试图获取 属性 的非对象 eloquent 关系，处理错误

Laravel 5.1 trying to get property of non object eloquent relationship, handle error

php

laravel

eloquent

laravel-5

laravel-5.1

Laravel 5.1 试图获取属性的非对象 eloquent 关系，处理错误