根据属性? 组织数组中的对象

Question

如何根据属性组织对象数组？例如，假设我有这个：

import UIKit
import SpriteKit

struct Person {

    let name : String!
    let age : Int!
    let charcter : characterType!

    enum characterType {
        case happy, sad, mad, scared, excited
    }
}

let people : [Person] = [

    Person(name: "Bob", age: 10, charcter: Person.characterType.happy),
    Person(name: "Joe", age: 45, charcter: Person.characterType.sad),
    Person(name: "Tom", age: 105, charcter: Person.characterType.scared),
    Person(name: "Mad", age: 3, charcter: Person.characterType.mad)

]

如何根据 character type 组织 people 数组？我希望所有生气的人都先是，然后是快乐，然后是悲伤，然后是害怕。

我该怎么做？ var newArray : [Person] ...

还有一件事我已经尝试过以下方法：

   func organizeArray(){

    var newArray = [Person]()

    var array1 = []
    var array2 = []
    var array3 = []
    var array4 = []
    var array5 = []

    for person in people {
        switch person.charcter {
            case happy...
                append to array 1
            case mad...
            append to array 2

so on...

        }

    }
    newArray = array1 + array2 + array3 + array4 + array5
}

但是当我运行这需要 XCode 永远索引。如果我删除此功能，一切正常。我想要一个简单的解决方案，并且不会导致 XCode 永远索引（很多）。

Answer 1

你在做什么，是为每种字符类型创建一个单独的数组，然后将它们连接在一起。这效率不高。正如 the-paramagnetic-croissant 所建议的那样，您应该使用 swift 数组的排序功能，并结合以这种方式将原始值关联到枚举类型的可能性：

struct Person {
    let name : String
    let age : Int
    let charcter : characterType

    enum characterType: Int {
       case mad = 0, happy, sad, scared, excited
   }
}

let people : [Person] = [
    Person(name: "Bob", age: 10, charcter: Person.characterType.happy),
    Person(name: "Joe", age: 45, charcter: Person.characterType.sad),
    Person(name: "Tom", age: 105, charcter: Person.characterType.scared),
    Person(name: "Mad", age: 3, charcter: Person.characterType.mad) 
]

let newArray = people.sorted { [=10=].charcter.rawValue < .charcter.rawValue }

println(newArray[0].charcter.rawValue) // Mad
println(newArray[1].charcter.rawValue) // Happy
println(newArray[2].charcter.rawValue) // Sad
println(newArray[3].charcter.rawValue) // Scared

根据属性? 组织数组中的对象

Organize objects in an array depending on their property?

arrays

swift

ios8

根据 属性? 组织数组中的对象

Organize objects in an array depending on their property?

arrays

swift

ios8

根据属性? 组织数组中的对象