如何处理将重复的 int 输入到 Int、String 的 2D SortedList 中

Question

我以前没有使用 SortedLists 的经验，并且由于尝试在列表中输入重复的整数而遇到错误 "An entry with the same key already exists"。这是我的疏忽，认为这不会发生（这很愚蠢）。

列表如下所示：

("503", "This is a sentence")
("364", "Oh and another one")
("329", "Yes sentences woo!")
("136", "You gets the point")

抛出错误的函数是：

    protected void buildSummary()
    {
        scoreCoord2 = -1;
        for (int x1 = 0; x1 < results.Length; x1++)
        {
            SortedList<int, string> paragraphScoreslist = new SortedList<int, string>();
            for (int x2 = 0; x2 < results[x1].Length; x2++)
            {
                scoreCoord2++;
                paragraphScoreslist.Add(intersectionSentenceScores[scoreCoord2], results[x1][x2]);
            }
            var maxValue = paragraphScoreslist.Max(k => k.Key);
            string topSentence = string.Empty;
            if (paragraphScoreslist.TryGetValue(maxValue, out topSentence))
            {
                TextboxSummary.Text += topSentence + "\n";
            }
        }
    }

它中断的具体行是：

    paragraphScoreslist.Add(intersectionSentenceScores[scoreCoord2], results[x1][x2]);

排序后的列表包含一段句子和程序计算的句子分数。然后我需要得分最高的句子，但不知道如何处理这个错误。

我觉得这两个句子都是 "top" 并且都以某种方式输出，或者其中一个被选为顶部，除非已经有更高的句子。

Answer 1

SortedList<int, List<string>> paragraphScoreslist = new SortedList<int, List<string>>();
        for (int x2 = 0; x2 < results[x1].Length; x2++)
        {
            scoreCoord2++;
            if(paragraphScoreslist.ContainsKey(intersectionSentenceScores[scoreCoord2])
            {
               paragraphScoreslist[intersectionSentenceScores[scoreCoord2]].Add(results[x1][x2]);
            }
            else
            {
                paragraphScoreslist.Add(intersectionSentenceScores[scoreCoord2], new List<string>{results[x1][x2]});
            }

        }

然后获取流行音乐的顶部：

 List<string> topSentences;
 if (paragraphScoreslist.TryGetValue(maxValue, out topSentences))
 {
      foreach(string topSentence in topSentences)
      {
         TextboxSummary.Text += topSentence + "\n";
      }
 }

Answer 2

您可以创建一个 ScoredSentence class，例如

，而不是使用 SortedList

public class ScoredSentence 
{
    public string sentence { get; set; }
    public int score { get; set; }

    public ScoredSentence(string sentence, int score)
    {
        this.sentence = sentence;
        this.score = score;
    }
}

然后你可以把它全部存储在一个列表中，比如

var s1 = new ScoredSentence("this is a sentence", 2);
var s2 = new ScoredSentence("hey there buddy", 4);
var s3 = new ScoredSentence("This is bad", 0);
var scores = new List<ScoredSentence> {s1,s2,s3};

然后你可以用

拉出最高分

int max = scores.Max(s => s.score);

或找到得分最高的句子

var maxScoredSentence = scores.First(s => s.score == max);

这是您的代码中的样子

for (int x1 = 0; x1 < results.Length; x1++)
    {
        List<ScoredSentence> scoreslist = new List<ScoredSentence>();
        for (int x2 = 0; x2 < results[x1].Length; x2++)
        {
            scoreCoord2++;
            scoreslist.Add(new ScoredSentence(results[x1][x2],intersectionSentenceScores[scoreCoord2]));
        }
        var maxValue = scoreslist.Max(s => s.score);
        string topSentence = string.Empty;

        TextboxSummary.Text += scoreslist.First(s => s.score == maxValue).sentence + "\n";

    }

如何处理将重复的 int 输入到 Int、String 的 2D SortedList 中

How to handle having a duplicate int entered into a 2D SortedList of Int, String

c#

error-handling

list

sortedlist