SQL 服务器的语法无效
Invalid syntax for SQL Server
我试图在 SQL 服务器中执行以下查询,但它抛出了一个错误。我该如何解决?
select
T.T_Email
from
Stu_Question S, Tutor_Answer T
where
S.S_Quest_Id = '4f7a1518-a765-40c0-ae53-3ee61eef6673'
and S.S_Quest_Id = T.S_Quest_Id
and (T_Email,T_Answer_Update_Status)
IN (T_Email, Select MAX(T_Answer_Update_Status)
from Tutor_Answer
where S_Quest_Id='4f7a1518-a765-40c0-ae53-3ee61eef6673'
group by T_Email)
and S.S_Quest_Update_Status = (Select MAX(S_Quest_Update_Status)
from Stu_Question
where S_Quest_Id='4f7a1518-a765-40c0-ae53-3ee61eef6673')
这是您声明中令人反感的部分:
and (T_Email,T_Answer_Update_Status)
IN (T_Email, Select MAX(T_Answer_Update_Status)
from Tutor_Answer
where S_Quest_Id='4f7a1518-a765-40c0-ae53-3ee61eef6673'
group by T_Email)
你到底想在这里做什么???
T-SQL 的 IN
运算符一次处理 一个 列 - 像这样:
WHERE T_EMail IN (SELECT EMail FROM .....)
marc_s
正确指出了您的查询中有问题的部分。
您必须尝试将其转换为联接。这是我的做法:
select T.T_Email
from Stu_Question S
join (select T_Email,
row_number() over (partition by S_Quest_Id order by S_Quest_Update_Status desc) as rn
from Tutor_Answer) T
on T.S_Quest_Id=S.S_Quest_Id
and T.rn = 1
where S.S_Quest_Id='4f7a1518-a765-40c0-ae53-3ee61eef6673'
AND S.S_Quest_Update_Status=(Select MAX(S_Quest_Update_Status)
from Stu_Question
where S_Quest_Id='4f7a1518-a765-40c0-ae53-3ee61eef6673')
请注意,您绝对可以进一步改进它。但它应该能让你继续前进。
我试图在 SQL 服务器中执行以下查询,但它抛出了一个错误。我该如何解决?
select
T.T_Email
from
Stu_Question S, Tutor_Answer T
where
S.S_Quest_Id = '4f7a1518-a765-40c0-ae53-3ee61eef6673'
and S.S_Quest_Id = T.S_Quest_Id
and (T_Email,T_Answer_Update_Status)
IN (T_Email, Select MAX(T_Answer_Update_Status)
from Tutor_Answer
where S_Quest_Id='4f7a1518-a765-40c0-ae53-3ee61eef6673'
group by T_Email)
and S.S_Quest_Update_Status = (Select MAX(S_Quest_Update_Status)
from Stu_Question
where S_Quest_Id='4f7a1518-a765-40c0-ae53-3ee61eef6673')
这是您声明中令人反感的部分:
and (T_Email,T_Answer_Update_Status)
IN (T_Email, Select MAX(T_Answer_Update_Status)
from Tutor_Answer
where S_Quest_Id='4f7a1518-a765-40c0-ae53-3ee61eef6673'
group by T_Email)
你到底想在这里做什么???
T-SQL 的 IN
运算符一次处理 一个 列 - 像这样:
WHERE T_EMail IN (SELECT EMail FROM .....)
marc_s
正确指出了您的查询中有问题的部分。
您必须尝试将其转换为联接。这是我的做法:
select T.T_Email
from Stu_Question S
join (select T_Email,
row_number() over (partition by S_Quest_Id order by S_Quest_Update_Status desc) as rn
from Tutor_Answer) T
on T.S_Quest_Id=S.S_Quest_Id
and T.rn = 1
where S.S_Quest_Id='4f7a1518-a765-40c0-ae53-3ee61eef6673'
AND S.S_Quest_Update_Status=(Select MAX(S_Quest_Update_Status)
from Stu_Question
where S_Quest_Id='4f7a1518-a765-40c0-ae53-3ee61eef6673')
请注意,您绝对可以进一步改进它。但它应该能让你继续前进。