handleOpenURL 不会触发 iOS Swift 2

Question

我正在尝试为我正在开发的应用程序获取 Instagram 身份验证令牌，我打开了 safari 应用程序，我可以登录，然后它会将我送回该应用程序，但是当它把我转回应用程序，handleOpenURL 未在 AppDelegate 中触发。这是我的代码示例：

import UIKit

@UIApplicationMain
class AppDelegate: UIResponder, UIApplicationDelegate {

var window: UIWindow?

....
    func application(application: UIApplication, handleOpenURL url: NSURL) -> Bool {
        InstagramAPIManager.sharedInstance.processOAuthStep1Response(url)
        print(url)
        print("handleOpenURL")
        return true
    }

}

这里是我的 API 触发 safari 打开的管理器代码：

import Foundation
import Alamofire

class InstagramAPIManager {
    static let sharedInstance = InstagramAPIManager()

    func startOAuth2Login() {
        let clientID: String = "abcdefg"
        let authPath:String = "https://api.instagram.com/oauth/authorize/?client_id=\(clientID)&redirect_uri=grokInstagram://?aParam=paramVal&response_type=code"
        if let authURL:NSURL = NSURL(string: authPath)
        {
            UIApplication.sharedApplication().openURL(authURL)
        }
    }
....

}

如有任何帮助，我们将不胜感激！

Answer 1

在 iOS 9 中，application:handleOpenURL: 已弃用。相反，您应该使用：

func application(app: UIApplication, 
    openURL url: NSURL, options: [String : AnyObject]) -> Bool {

Answer 2

正确的语法似乎是

func application(_ app: UIApplication,
                          open url: URL,
                          options: [UIApplicationOpenURLOptionsKey : Any]) -> Bool {
    return true
}

根据https://developer.apple.com/reference/uikit/uiapplicationdelegate/1623112-application

handleOpenURL 不会触发 iOS Swift 2

handleOpenURL won't trigger iOS Swift 2

ios

instagram-api

swift2