Java 中未使用的参数与数组

Question

我正在编写一个程序，从中间拆分一个偶数长度的数组，并找到两半中最大的一个。这是我到目前为止的代码，但是我不确定要将什么作为 calculateAverage 方法中的第一个参数传递。如有任何帮助，我们将不胜感激。

public int calculateAverage(int[] scores, int start, int end) {
    int count = 0;
    int score = 0;
    for (int i = start; i < end; i++) {
        score += scores[i];
        count++;
    }

    score = (score / count);

    return score;
}

public int scoresAverage(int[] scores) {
    int endOfFirstHalf = (scores.length / 2) - 1;
    int firstHalf = calculateAverage(scores[], scores[0], endOfFirstHalf);
    int secondHalf = calculateAverage(scores[], scores[scores.length / 2],     scores[scores.length - 1]);

    if (firstHalf < secondHalf) {
        return secondHalf;
    } else {
        return firstHalf;
    }

}

Answer 1

请试试这个。

public class TestBench{
        public static void main(String[] args){
            int[] i = {1,2,3,4};
            System.out.println(scoresAverage(i));
       }

        public static double calculateAverage(int[] scores, int start, int end) {
            int count = 0;
            double score = 0.0;
            for (int i = start; i <= end; i++) {
                score += scores[i];
                count++;
            }
            score = (score / count);

            return score;
        }

        public static double scoresAverage(int[] scores) {
            int endOfFirstHalf = (scores.length / 2) - 1;
            double firstHalf = calculateAverage(scores, 0, endOfFirstHalf);
            double secondHalf = calculateAverage(scores, endOfFirstHalf + 1, scores.length - 1);

            if (firstHalf < secondHalf) {
                return secondHalf;
            } else {
                return firstHalf;
            }
        }
    }

Answer 2

int secondHalf = calculateAverage(scores[scores.length / 2], 
                                        scores[scores.length - 1]);

1.you 方法名称有错别字。

2.pass 一个数组名。应该有3个参数，不是2个。

它看起来应该有点像：

int firstHalf = calculateAverage(scores, 0, endOfFirstHalf);
    int secondHalf = calculateAverage(scores,scores[scores.length / 2], 
                                            scores[scores.length - 1]);

Answer 3

您应该传递您的函数所期望的。无论如何，这是修改后的代码：

public class UnusedParam {
public int calculateAverage(int[] scores, int start, int end) {
    int count = 0;
    int score = 0;

    for (int i = start; i <= end; i++) {
        score += scores[i];
        count++;
    }
    score = (score / count);

    return score;
}

public int scoresAverage(int[] scores) {
    int endOfFirstHalf = (scores.length / 2) - 1;
    int firstHalf = calculateAverage(scores, 0, endOfFirstHalf);
    int secondHalf = calculateAverage(scores,scores.length / 2, scores.length - 1);

    if (firstHalf == secondHalf) {
        System.out.print("First Half is the same as Second Half");
        return secondHalf;
    }
    else if (firstHalf < secondHalf) {
        System.out.print("Second Half is the largest");
        return secondHalf;
    } 
    else {
        System.out.print("First Half is the largest");
        return firstHalf;
    }
}

public static void main(String[] args) {

    int[] scores = {1,2,3,4,5,6,7,8};

    UnusedParam up = new UnusedParam();
    int retVal = up.scoresAverage(scores);
    System.out.println(", "+retVal);
}
}

Java 中未使用的参数与数组

Unused parameters in Java with array

java

arrays

parameters

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